我需要将我创建的链表保存到文件中,但我希望用户帐户的每个部分都是自己的元素。即(用户名,密码,电子邮件,姓名,品种,性别,年龄,州,爱好)。但是我的代码出了问题,每个帐户都是自己的元素。任何帮助都会很棒!
此处还有指向我的帐户类的链接,用于创建链接列表 http://pastebin.com/jnBrcnP1
链接列表如下所示:
tobi
tobi123
tobi@hotmail.com
tobi
Mixed Breed
Male
1-2
Virginia
Walking
peppy
peppy123
peppy@hotmail.com
peppy
Chihuahua
Male
5-6
Virginia
Eating
保存到这样的文件:
tobitobi123tobi@hotmail.comtobiMixed BreedMale1-2VirginiaWalking
peppypeppy123peppy@hotmail.compeppyChihuahuaMale5-6VirginiaEating
创建链接列表的代码:
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.LinkedList;
public class Main extends javax.swing.JFrame implements ActionListener{
public static String readLine(BufferedReader br) throws IOException {
String rl = br.readLine();
if (rl.trim().length() > 2){
return rl;
}else return readLine(br);
}
public static void main(String[] args) {
LinkedList<Account> account = new LinkedList<Account>();
try
{
read(account, "output.txt");
} catch (Exception e)
{
System.err.println(e.toString());
}
display(account);
}
public static void read(LinkedList<Account> account, String inputFileName) throws java.io.IOException
{
BufferedReader infile = new BufferedReader(new FileReader(inputFileName));
while(infile.ready())
{
String username = readLine(infile);
String password = readLine(infile);
String email = readLine(infile);
String name = readLine(infile);
String breed = readLine(infile);
String gender = readLine(infile);
String age = readLine(infile);
String state = readLine(infile);
String hobby = readLine(infile);
Account a = new Account(username, password, email, name, breed, gender, age, state, hobby);
account.add(a);
a.showList();
}
infile.close();
}
public static void display(LinkedList<?> c)
{
for (Object e : c)
{
System.out.println(e);
}
}
将链接列表保存到文件的代码:
String file_name = "output.txt";
try {
FileWriter fstream = new FileWriter(file_name);
BufferedWriter out = new BufferedWriter(fstream);
ListIterator itr = account.listIterator();
while (itr.hasNext()) {
Account element = (Account) itr.next();
out.write("" + element);
out.newLine();
}
out.close();
System.out.println("File created successfully.");
} catch (Exception e) {
}
答案 0 :(得分:1)
这是Account
中的问题:
public String toString() {
return ""+username+"\n"+password+"\n"+email+"\n"+name+
"\n"+breed+"\n"+gender+"\n"+age+"\n"+state+"\n"+hobby;
}
您假设 \n
是合适的行结尾。我的猜测是你在Windows上运行,它将是\r\n
。就个人而言,我认为你的“编写”代码最好不要使用toString()
,而是写出行本身 - 毕竟,它知道它想要使用的格式。
(另外,我会advise against使用"" + ...
作为将值转换为字符串的方式...)