Question

我有以下模型：部门，项目，部门项目，员工和成员资格。部门有许多项目和项目有许多员工通过成员资格分配角色。我正在尝试创建一个InlineFormset，以便EU可以将Employee的角色分配给多个项目。

我的模板呈现正确的标签和字段，但Departmentprojects标签和字段不显示项目的名称。它只显示“Departmentprojects对象”。如何让表单呈现项目名称而不是“Departmentprojects object”？

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浏览器中的当前模板：

Departmentproject标签:(下拉菜单中有两个选项列为“Departmentprojects对象”）职责：项目经理

浏览器中的所需模板：

部门项目名称1：项目经理

部门项目名称2：其他一些角色

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模型：

class Projects(models.Model):
    name = models.CharField(max_length=20)
    def __unicode__(self):
        return self.name

class Department(models.Model):
    name = models.CharField(max_length=20)
    def __unicode__(self):
        return self.name

class Employees(models.Model):
    name = models.CharField(max_length=15)
    def __unicode__(self):
        return self.name

class Departmentprojects(models.Model):
    department = models.ForeignKey(Department)
    projects = models.ForeignKey(Projects)
    members = models.ManyToManyField(Employees, through='Membership')

class Membership(models.Model):
    departmentprojects = models.ForeignKey(Departmentprojects)
    employees = models.ForeignKey(Employees)
    role = models.CharField(max_length=20)

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查看

def addtoprojects(request, employees_id):
    e = get_object_or_404(Employees, pk=employees_id)
    ProjectsInlineFormSet = inlineformset_factory(Employees, Membership, max_num=1)
    if request.method == "POST":
        formset = ContactInlineFormSet(request.POST, instance=e)
        if formset.is_valid():
            formset.save()
    else:
        formset = ProjectsInlineFormSet(instance=e)
    return render_to_response('gcstest/contact.html', {'e': e, 'formset': formset}, context_instance=RequestContext(request))

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TEMPLATE

<form method="post" action="/assign_to_project/{{ employees.id }}/">
    {% csrf_token %}
    <table>
        {{ formset }}
    </table>
    <input type="submit" value="Submit"/>
</form>

Answer 1

向Departmentprojects模型添加__unicode__方法，例如

class Departmentprojects(models.Model):
    department = models.ForeignKey(Department)
    projects = models.ForeignKey(Projects)
    members = models.ManyToManyField(Employees, through='Membership')

    def __unicode__(self):
        return "%s > %s" % (self.department, self.projects)

DJANGO：如何在表单中呈现模型对象名称而不是文字“模型对象”？

1 个答案: