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Question

如何使用变量更改元素的颜色？

假设我们有四个字符串（颜色）。我需要给每个类元素赋予不同的一个，1,2,3,4,1,2,3 ......等等：

function pressLineColors() {

    var a = "#eee",
    b = "#123",
    c = "#fff",
    d = "#ae23e5";

     $('.pressLine').each(function (i) {
         //go througt each of this, and give them colors, so when new elements
        // appear, give them next color. 
     });
}

第一个元素sholud有颜色 a ，第二个 b ，第三个 c ，第四个 d ，第五个< strong> a ，...

Answer 1

function pressLineColors() {

    //setup array of colors and a variable to store the current index
    var colors = ["#eee", "#123", "#fff", "#ae23e5"],
        curr   = 0;

    //loop through each of the selected elements
    $.each($('.pressLine'), function (index, element) {

        //change the color of this element
        $(this).css('color', colors[curr]);

        //increment the current index
        curr++;

        //if the next index is greater than then number of colors then reset to zero
        if (curr == colors.length) {
            curr = 0;
        }
    });
}

以下是演示：http://jsfiddle.net/SngJK/

更新

您还可以使用此答案的评论中的建议来缩短代码：

function pressLineColors() {
    var colors = ["#eee", "#123", "#fff", "#ae23e5"],
        len    = colors.length;
    $.each($('.pressLine'), function (index, element) {
        $(this).css('color', colors[index % len]);
    });
}

以下是演示：http://jsfiddle.net/SngJK/2/

更新

您还可以使用.css('color', function (){})遍历每个元素，返回您想要制作元素的颜色：

$('.pressLine').css('color', function (index, style) {
    return colors[index % len];
});

以下是演示：http://jsfiddle.net/SngJK/4/

Answer 2

function pressLineColors() {
  var a = ["#eee","#123","#fff","#ae23e5"];

  $('.pressLine').each(function (i, ele) {
    $(ele).css("color", a[i % a.length]);
  });
}

Answer 3

将这些颜色放在数组中

function pressLineColors() {

a = new Array();

a[0] = "#eee",
a[1] = "#123",
a[2] = "#fff",
a[3] = "#ae23e5";

var c = 0;
var size = a.length;

 $('.pressLine').each(function (i) {

      this.style.color = a[c];
      c++;
      if(c > size) c = 0;
  });
}

Answer 4

创建一个变量来跟踪，一个单独的函数将允许您稍后添加元素并跟踪

/* colors in indexable array*/
var colors=["#eee", "#123","#fff","#ae23e5"];

var counter=0;
$('.pressLine').each(function () {
         $(this).css('color', colors[nextColorIndex()]);

});

function nextColorIndex(){
    var ctr=counter;
         counter=(++counter <colors.length) ? counter++ :0
         return ctr;
}

Answer 5

使用addClass

http://api.jquery.com/addClass/

或

http://api.jquery.com/css/

Answer 6

您需要将列表放入类似数组的对象，然后按索引访问;

function pressLineColors() {

var colors = [ a = "#eee",
b = "#123",
c = "#fff",
d = "#ae23e5"];

 $('.pressLine').each(function (i) {
     //go througt each of this, and give them colors, so when new elements
    // appear, give them next color. 

   $(this).css("color" , colors[i]);
 });
}

如何动态改变元素的颜色？

6 个答案:

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