Question

我正在使用python和Qt开发一个应用程序。

我使用Qt设计了2个主窗口，即.QMainWindow（不是QWidget或QDialog）。

让它成为。

1.LoginWindow - LoginUI（Qt）

2.StuffWindow --- StuffUI

首先我应该显示登录窗口。



然后我应该将用户名传递给StaffWindow（管理内容所需的用户名）



应显示StaffWindow并关闭LoginWindow ..

我怎样才能实现这一目标？救救我..

Answer 1

无论您的描述如何，我认为您的LoginWindow应该是QDialog，而您的StuffWIndow应该是MainWindow，并且功能如下......

应创建您的StuffWindow MainWindow（未显示）
调用login()方法创建并执行（）您的登录QDialog作为应用程序MODAL对话框
立即启动app.exec_（）事件循环，并等待用户与登录
用户与登录对话框进行交互，关闭对话框的结果将允许您的应用程序检查其值并选择显示其主界面。

这是一个快速概述：

class MainWindow():

    def login():
        loginDialog = LoginDialog()

        # this is modal. wait for it to close
        if loginDialog.exec_():
            # dialog was accepted. check its values and maybe:
            self.show()

        else:
            # maybe reshow the login dialog if they rejected it?
            loginDialog.exec_()


if __name__ == "__main__":

    app = QApp
    win = MainWindow()
    win.login()
    app.exec_()

Answer 2

我同意大多数提出的jdi点，但我更喜欢略有不同的方法。

LoginWindow应为QDialog以MODAL开头。
检查exec_()（即accept/reject）的退货情况，以便登录或取消/退出。
检查LoginWindow
如果成功登录，请使用提供的参数启动MainWindow

在看到jdi的答案之前，我开始编写一个简单的例子。我不妨把它放在这里。

import sys
from PyQt4 import QtGui, QtCore

class LoginDialog(QtGui.QDialog):
    def __init__(self, parent=None):
        super(LoginDialog, self).__init__(parent)

        self.username = QtGui.QLineEdit()
        self.password = QtGui.QLineEdit()
        loginLayout = QtGui.QFormLayout()
        loginLayout.addRow("Username", self.username)
        loginLayout.addRow("Password", self.password)

        self.buttons = QtGui.QDialogButtonBox(QtGui.QDialogButtonBox.Ok | QtGui.QDialogButtonBox.Cancel)
        self.buttons.accepted.connect(self.check)
        self.buttons.rejected.connect(self.reject)

        layout = QtGui.QVBoxLayout()
        layout.addLayout(loginLayout)
        layout.addWidget(self.buttons)
        self.setLayout(layout)

    def check(self):
        if str(self.password.text()) == "12345": # do actual login check
            self.accept()
        else:
            pass # or inform the user about bad username/password


class MainWindow(QtGui.QMainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)

        self.label = QtGui.QLabel()
        self.setCentralWidget(self.label)

    def setUsername(self, username):
        # do whatever you want with the username
        self.username = username
        self.label.setText("Username entered: %s" % self.username)


if __name__ == "__main__":
    app = QtGui.QApplication(sys.argv)

    login = LoginDialog()
    if not login.exec_(): # 'reject': user pressed 'Cancel', so quit
        sys.exit(-1)      

    # 'accept': continue
    main = MainWindow()
    main.setUsername(login.username.text()) # get the username, and supply it to main window
    main.show()

    sys.exit(app.exec_())

Answer 3

虽然这与您的问题没有直接关系，但您应始终为密码字段设置QLineEdit.EchoMode，如下所示（请参阅here）：

self.password.setEchoMode(QtGui.QLineEdit.Password)

Answer 4

这是Avari的PyQt5更新版本。添加了一些异常处理以显示如何捕获一些错误（在编写您的东西时。享受！

#!/usr/bin/env python
# -*- coding: utf-8 -*-

# Ref to this OP question. https://stackoverflow.com/questions/9689053/how-to-communicate-or-switch-between-two-windows-in-pyqt4

import sys
from PyQt5 import QtGui, QtCore, QtWidgets
from PyQt5.QtWidgets import QApplication, QDialog, QDialogButtonBox, QFormLayout, QLabel, QLineEdit, QWidget, QVBoxLayout

class LoginDialog(QtWidgets.QDialog):
    def __init__(self, parent=None):
        super(LoginDialog, self).__init__(parent)

        self.username = QLineEdit()
        self.password = QLineEdit()
        loginLayout = QFormLayout()
        loginLayout.addRow("Username", self.username)
        loginLayout.addRow("Password", self.password)

        self.buttons = QDialogButtonBox(QDialogButtonBox.Ok | QDialogButtonBox.Cancel)
        self.buttons.accepted.connect(self.check)
        self.buttons.rejected.connect(self.reject)

        layout = QVBoxLayout()
        layout.addLayout(loginLayout)
        layout.addWidget(self.buttons)
        self.setLayout(layout)

    def check(self):
        if str(self.password.text()) == "12345": # do actual login check
            self.accept()
        else:
            pass # or inform the user about bad username/password

    def my_exception_hook(exctype, value, traceback):
        # Print the error and traceback
        print(exctype, value, traceback)
        # Call the normal Exception hook after
        sys._excepthook(exctype, value, traceback)
        sys.exit(1)

    # Back up the reference to the exceptionhook
    sys._excepthook = sys.excepthook

    # Set the exception hook to our wrapping function
    sys.excepthook = my_exception_hook


class MainWindow(QtWidgets.QMainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)

        self.label = QLabel()
        self.setCentralWidget(self.label)

    def setUsername(self, username):
        # do whatever you want with the username
        self.username = username
        self.label.setText("Username entered: %s" % self.username)


if __name__ == "__main__":
    app = QApplication(sys.argv)

    login = LoginDialog()
    if not login.exec_(): # 'reject': user pressed 'Cancel', so quit
        sys.exit(-1)      # instead of -1 another action can be triggered here.     

    # 'accept': continue
    main = MainWindow()

    # get the username, and supply it to main window
    main.setUsername(login.username.text())
    main.show()

    sys.exit(app.exec_())

Answer 5

匹配用户名和密码。

'get /min/*': { 
  skipAssets: false,
  fn: [
    require('serve-static')('.tmp/public', {
      maxAge: process.env.NODE_ENV !== 'production' ? 0 : 31557600000,
      etag: false
    }),
  ]
}

如何在PyQt中的两个窗口之间进行通信或切换？

5 个答案: