Question

我在我的视图功能中有这个：

emit([doc.address.country,doc.address.state, doc.address.city], doc);

当我查询搜索时，我需要填充数组的所有3个元素，例如：

?key=["US","NY","New York"]

这将产生我的记录，但举个例子，我只想返回美国的所有内容，例如：

?key=["US"]

或在美国和州......

?key=["US","NY"]

或者......或许我想也许我只想要来自纽约的所有记录......（我知道下面的内容不起作用）

?key=["","NY"]

如果你想将数组中的一个元素留空，我真的不知道如何搜索？

Answer 1

首先：

key = [“US”]将无法在数组键[“US”，“NY”]上工作，因为您正在寻找一个完全[“US”]的键。相反，你必须使用

startkey=["US"]&endkey=["US",{}]

然后这些键在结果集中：

["DE","Bavaria","Munich"]   <---- NO ! "DE" is out of Range of startkey
["US","FL","Miami"]         <---- YES, starts with "US"
["US","NY","New York"]      <---- YES, starts with "US"
["VE","XX","Vencuela City"] <---- NO ! "VE" is out of Range of endkey

同时工作：

startkey=["US","FL"]&endkey=["US","FL",{}]

结果：

["DE","Bavaria","Munich"]   <---- NO ! "DE" is out of Range of startkey
["US","FL","Miami"]         <---- YES, starts with "US","FL"
["US","NY","New York"]      <---- NO, "US","NY" is out of Range of endkey
["VE","XX","Vencuela City"] <---- NO ! "VE" is out of Range of endkey

<强>第二你不能在左侧有空白..所以你必须写一些更多的发射：（如果不需要查询，则不必发出第二个和第三个数组项）

查看“byStateCityCountry”：

emit([doc.address.state, doc.address.city,address.country], doc);

查看“byCityStateCountry”：

emit([address.city,doc.address.state, doc.address.country], doc);

只是在第一个位置放置一个标志来确定查询类型，因此您可以在一个视图中执行所有操作：

emit([1,address.country,doc.address.state, doc.address.city], doc);
emit([2,doc.address.state, doc.address.city,address.country], doc);
emit([3,address.city,doc.address.state, doc.address.country], doc);

用法：

?startkey=[1,"US"]&endkey=[1,"US",{}]
?startkey=[2,"FL"]&endkey=[2,"FL",{}]
?startkey=[3,"Miami"]&endkey=[3,"Miami",{}]

couchdb搜索或过滤关键数组

1 个答案: