我的C#项目中有一个exe文件引用。如何从我的代码中调用该exe文件?
答案 0 :(得分:244)
using System.Diagnostics;
class Program
{
static void Main()
{
Process.Start("C:\\");
}
}
如果您的应用程序需要cmd参数,请使用以下内容:
using System.Diagnostics;
class Program
{
static void Main()
{
LaunchCommandLineApp();
}
/// <summary>
/// Launch the application with some options set.
/// </summary>
static void LaunchCommandLineApp()
{
// For the example
const string ex1 = "C:\\";
const string ex2 = "C:\\Dir";
// Use ProcessStartInfo class
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.CreateNoWindow = false;
startInfo.UseShellExecute = false;
startInfo.FileName = "dcm2jpg.exe";
startInfo.WindowStyle = ProcessWindowStyle.Hidden;
startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2;
try
{
// Start the process with the info we specified.
// Call WaitForExit and then the using statement will close.
using (Process exeProcess = Process.Start(startInfo))
{
exeProcess.WaitForExit();
}
}
catch
{
// Log error.
}
}
}
答案 1 :(得分:16)
答案 2 :(得分:5)
示例:
System.Diagnostics.Process.Start("mspaint.exe");
编译代码
复制代码并将其粘贴到控制台应用程序的 Main 方法中。 替换&#34; mspaint.exe&#34;以及要运行的应用程序的路径。
答案 3 :(得分:4)
实施例:
Process process = Process.Start(@"Data\myApp.exe");
int id = process.Id;
Process tempProc = Process.GetProcessById(id);
this.Visible = false;
tempProc.WaitForExit();
this.Visible = true;
答案 4 :(得分:1)
我知道这是很好的答案,但是如果您有兴趣,我写了一个库,使执行命令更加容易。