Question

我通过javascript SDK检索访问令牌，并通过windows.location将其传递给服务器：

<script src='https://connect.facebook.net/en_US/all.js'></script>
<!-- Load javascript facebook connector -->
<script>
    FB.init({
            appId : '<?=$app_id;?>',
            status : true, // check login status
            cookie : true, // enable cookies to allow the server to access the session
            xfbml : true // parse XFBML
    });
</script>
<script type="text/javascript">
    function getToken(){
    FB.login(function(response) {
        if (response.authResponse) {
            var access_token = response.authResponse.accessToken;
            window.location="<?=$_SERVER['PHP_SELF'];?>?accessToken="+access_token;
        } else {
            return false;
        }
    }, {scope:'user_likes,friends_likes'});
}
</script>

PHP代码：

<?php
  $app_id = 'MY_APP_ID';
  $app_secret = 'MY_APP_SECRET';
  $page_id= 'MY_PAGE_ID';

  if(isset($_GET['accessToken'])){
  // Run fql query
  $fql_query_url = 'https://graph.facebook.com/'
. '/fql?q=SELECT+uid+FROM+page_fan+WHERE+page_id='.$page_id.'+AND+uid+IN+(SELECT+uid2+FROM+friend+WHERE+uid1=me())&'.$_GET['accessToken'];
  echo $fql_query_url;
  $fql_query_result = file_get_contents($fql_query_url);
  $fql_query_obj = json_decode($fql_query_result, true);

  //display results of fql query
  foreach($fql_query_obj as $v1){
    foreach($v1 as $v2){
        $x++;
    }
}
echo "You have ".$x." friends who 'like' us";

}

当我回显$ fql_query_url并浏览浏览器中的url时，facebook graph api answers

{
   "error": {
      "message": "An access token is required to request this resource.",
      "type": "OAuthException",
      "code": 104
   }
}

我做错了什么？我得到一个访问令牌，但似乎没有效果？

Answer 1

您在实际请求中遗漏了access_token，因为您只是将access_token添加到网址而未实际命名该参数。在将access_token=添加到网址之前添加$_GET['accessToken']。

让您的源可读以发现此类事情真的很棒：

$query = <<<FQL
SELECT uid FROM page_fan WHERE page_id = {$page_id} AND uid IN (
  SELECT uid2 FROM friend WHERE uid1 = me()
)
FQL;
$fql_query_url = 'https://graph.facebook.com/fql?q=' . rawurlencode($query);
$fql_query_url .= '&access_token=' . rawurlencode($_GET['accessToken']);

顺便说一下，通过GET参数传递access_token是一个非常糟糕的方法，试着避免这种情况。

通过javascript SDK检索的访问令牌在传递给php时似乎无效

1 个答案: