Question

我正在尝试在Android中实现语音识别代码。如何从Android中的数组列表中获取特定位置的元素？我尝试将arraylist转换为array并进行重新审核。代码仍无效。

package com.espeaker;


    public class EspeakerActivity extends Activity {

                    private static final int REQUEST_CODE = 1234;
            private ListView wordsList;


            /** Called when the activity is first created. */
            @Override
            public void onCreate(Bundle savedInstanceState) {
                  super.onCreate(savedInstanceState);
                  setContentView(R.layout.main);


                  Button speakButton = (Button) findViewById(R.id.speakButton);

                  wordsList = (ListView) findViewById(R.id.list);

                  // Disable button if no recognition service is present
                  PackageManager pm = getPackageManager();
                  List<ResolveInfo> activities = pm.queryIntentActivities(
                          new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH), 0);
                  if (activities.size() == 0)
                  {
                      speakButton.setEnabled(false);
                      speakButton.setText("Recognizer not present");
                  }
            }

    /**
     * Handle the action of the button being clicked
     */
    public void speakButtonClicked(View v)
    {
        startVoiceRecognitionActivity();
    }

    /**
     * Fire an intent to start the voice recognition activity.
     */
    private void startVoiceRecognitionActivity()
    {
        Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
        intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
                RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
        intent.putExtra(RecognizerIntent.EXTRA_PROMPT, "Voice recognition Demo...");
        startActivityForResult(intent, REQUEST_CODE);
    }

    /**
     * Handle the results from the voice recognition activity.
     */
    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data)
    {
        if (requestCode == REQUEST_CODE && resultCode == RESULT_OK)
        {
            // Populate the wordsList with the String values the recognition engine thought it heard
            ArrayList<String> matches = data.getStringArrayListExtra(
                    RecognizerIntent.EXTRA_RESULTS);
            wordsList.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,
                    matches));
            String[] array=matches.toArray(new String[matches.size()]);
           // ArrayList<String> places = new ArrayList<String>(
                //    Arrays.asList("black", "blue", "red"));
            ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, R.layout.list_item,matches);
              final AutoCompleteTextView input_text = (AutoCompleteTextView) findViewById(R.id.auto);
              Button button1 = (Button) findViewById(R.id.button1);
                     input_text.setAdapter(adapter);
            button1.setText(" "+array[0]);

           // button1.setText(""+matches);
             }
        super.onActivityResult(requestCode, resultCode, data);
    }
    }

Answer 1

也许以下内容对您有帮助。

arraylistname.get(position);

Answer 2

我的理解是，您希望在特定位置的ArrayList中获取元素。

假设您的列表包含整数1,2,3,4,5并且您想要获取值3.然后以下代码行将起作用。

ArrayList<Integer> list = new ArrayList<Integer>();
        if(list.contains(3)){//check if the list contains the element
            list.get(list.indexOf(3));//get the element by passing the index of the element
        }

您可以使用list.get(list.lastIndexOf(3))

的任何一种方式

Answer 3

public class DemoActivity extends Activity {
    /** Called when the activity is first created. */
    ArrayList<String> al = new ArrayList<String>();

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);



        // add elements to the array list

        al.add("C");
        al.add("A");
        al.add("E");
        al.add("B");
        al.add("D");
        al.add("F");

        // retrieve elements from array

        String data = al.get(pass the index here);
        System.out.println("Data is "+ data);

这是获取元素的另一种方式

        Iterator<String> it = al.iterator();
        while (it.hasNext()) {
            System.out.println("Data is "+ it.next());
        }
    }

Answer 4

在arraylist中，您有一个位置顺序而不是名义顺序，因此您需要事先知道需要选择的元素位置，或者必须在元素之间循环，直到找到需要使用的元素。为此，您可以使用迭代器和if，例如：

Iterator iter = list.iterator();
while (iter.hasNext())
{
    // if here          
    System.out.println("string " + iter.next());
}

Answer 5

我有一个要检索的数组位置列表，这对我有用。

  public void create_list_to_add_group(ArrayList<Integer> arrayList_loc) {
     //In my case arraylist_loc is the list of positions to retrive from 
    // contact_names 
    //arraylist and phone_number arraylist

    ArrayList<String> group_members_list = new ArrayList<>();
    ArrayList<String> group_members_phone_list = new ArrayList<>();

    int size = arrayList_loc.size();

    for (int i = 0; i < size; i++) {

        try {

            int loc = arrayList_loc.get(i);
            group_members_list.add(contact_names_list.get(loc));
            group_members_phone_list.add(phone_num_list.get(loc));


        } catch (Exception e) {
            e.printStackTrace();
        }


    }

    Log.e("Group memnbers list", " " + group_members_list);
    Log.e("Group memnbers num list", " " + group_members_phone_list);

}

Answer 6

你不能试试这个

for (WordList i : words) {
     words.get(words.indexOf(i));
 }

从Android中的数组列表中检索元素？

6 个答案: