我的代码似乎有误。但是我无法找到它。
class Class
def attr_accessor_with_history(attr_name)
attr_name = attr_name.to_s
attr_reader attr_name
attr_writer attr_name
attr_reader attr_name + "_history"
class_eval %Q{
@#{attr_name}_history=[1,2,3]
}
end
end
class Foo
attr_accessor_with_history :bar
end
f = Foo.new
f.bar = 1
f.bar = 2
puts f.bar_history.to_s
我希望它返回一个数组[1,2,3]
。但是,它不会返回任何内容。
答案 0 :(得分:5)
您不应该打开Class
来添加新方法。这就是模块的用途。
module History
def attr_accessor_with_history(attr_name)
attr_name = attr_name.to_s
attr_accessor attr_name
class_eval %Q{
def #{attr_name}_history
[1, 2, 3]
end
}
end
end
class Foo
extend History
attr_accessor_with_history :bar
end
f = Foo.new
f.bar = 1
f.bar = 2
puts f.bar_history.inspect
# [1, 2, 3]
这是你可能想写的代码(从名字来看)。
module History
def attr_accessor_with_history(attr_name)
attr_name = attr_name.to_s
class_eval %Q{
def #{attr_name}
@#{attr_name}
end
def #{attr_name}= val
@#{attr_name}_history ||= []
@#{attr_name}_history << #{attr_name}
@#{attr_name} = val
end
def #{attr_name}_history
@#{attr_name}_history
end
}
end
end
class Foo
extend History
attr_accessor_with_history :bar
end
f = Foo.new
f.bar = 1
f.bar = 2
puts f.bar_history.inspect
# [nil, 1]
答案 1 :(得分:5)
解决方案:
class Class
def attr_accessor_with_history(attr_name)
ivar = "@#{attr_name}"
history_meth = "#{attr_name}_history"
history_ivar = "@#{history_meth}"
define_method(attr_name) { instance_variable_get ivar }
define_method "#{attr_name}=" do |value|
instance_variable_set ivar, value
instance_variable_set history_ivar, send(history_meth) << value
end
define_method history_meth do
value = instance_variable_get(history_ivar) || []
value.dup
end
end
end
试验:
describe 'Class#attr_accessor_with_history' do
let(:klass) { Class.new { attr_accessor_with_history :bar } }
let(:instance) { instance = klass.new }
it 'acs as attr_accessor' do
instance.bar.should be_nil
instance.bar = 1
instance.bar.should == 1
instance.bar = 2
instance.bar.should == 2
end
it 'remembers history of setting' do
instance.bar_history.should == []
instance.bar = 1
instance.bar_history.should == [1]
instance.bar = 2
instance.bar_history.should == [1, 2]
end
it 'is not affected by mutating the history array' do
instance.bar_history << 1
instance.bar_history.should == []
instance.bar = 1
instance.bar_history << 2
instance.bar_history.should == [1]
end
end
答案 2 :(得分:2)
您可以在Sergios answer找到问题的解决方案。这里有一个解释,你的代码出了什么问题。
用
class_eval %Q{
@#{attr_name}_history=[1,2,3]
}
你执行
@bar_history = [1,2,3]
您在类级别执行此操作,而不是在对象级别执行此操作。
变量@bar_history
在Foo对象中不可用,但在Foo类中不可用。
用
puts f.bar_history.to_s
您可以在对象级别定义属性@bar_history上访问-never。
在课程级别定义阅读器时,您可以访问变量:
class << Foo
attr_reader :bar_history
end
p Foo.bar_history #-> [1, 2, 3]
答案 3 :(得分:2)
@Sergio Tulentsev的回答是有效的,但它促进了使用字符串评估的问题,这种做法通常充满了安全风险和其他意外,而输入并不是您所期望的。例如,如果有人打电话给塞尔吉奥的版本会发生什么(不要试试):
attr_accessor_with_history %q{foo; end; system "rm -rf /"; def foo}
通常可以在没有字符串评估的情况下更仔细地进行ruby元编程。在这种情况下,使用带有instance_variable_ [get | set]的闭包的简单插值和define_method,并发送:
module History
def attr_accessor_with_history(attr_name)
getter_sym = :"#{attr_name}"
setter_sym = :"#{attr_name}="
history_sym = :"#{attr_name}_history"
iv_sym = :"@#{attr_name}"
iv_hist = :"@#{attr_name}_history"
define_method getter_sym do
instance_variable_get(iv_sym)
end
define_method setter_sym do |val|
instance_variable_set( iv_hist, [] ) unless send(history_sym)
send(history_sym).send( :'<<', send(getter_sym) )
instance_variable_set( iv_sym, val @)
end
define_method history_sym do
instance_variable_get(iv_hist)
end
end
end
答案 4 :(得分:0)
这是应该做的。需要使用class_eval在Class中定义attr_writer。
class Class
def attr_accessor_with_history(attr_name)
attr_name = attr_name.to_s
attr_reader attr_name
#attr_writer attr_name ## moved into class_eval
attr_reader attr_name + "_history"
class_eval %Q{
def #{attr_name}=(value)
@#{attr_name}_history=[1,2,3]
end
}
end
end