使用PDO将数组数据插入数据库

时间:2012-03-11 20:43:11

标签: php html arrays forms pdo

有人可以向我解释如何将我输出的数组数据导入我的数据库中的行。

HTML

<form id="AddRecipeForm" method="post" action="includes/add-recipe.php" class="form-inline">    
    <input type="text" name="recipe[ingredient][1]" class="input-large" placeholder="Title 1"><input type="text" name="recipe[quantity][1]" class="input-large" placeholder="Quantity 1"><br /><br />   
    <input type="text" name="recipe[ingredient][2]" class="input-large" placeholder="Title 2"><input type="text" name="recipe[quantity][2]" class="input-large" placeholder="Quantity 2"><br /><br />   
    <input type="text" name="recipe[ingredient][3]" class="input-large" placeholder="Title 3"><input type="text" name="recipe[quantity][3]" class="input-large" placeholder="Quantity 3"><br /><br />
    <button type="submit" class="btn">Add Recipe</button>
</form>

这是传递给php表单:

foreach($_POST['recipe'] as $key=>$value)
    {   

    }

print_r($_POST);

并输出以下数组:

Array ( 
    [recipe] => Array ( 
        [ingredient] => Array ( 
            [1] => eggs 
            [2] => milk 
            [3] => flour
        ) [quantity] => Array ( 
            [1] => 12 
            [2] => 13 
            [3] => 14 
        ) 
    ) 
)

我需要将每个成分和数量导入我的数据库表中的新行。我正在使用PDO连接到我的数据库,但我不确定如何将数组中的数据插入到我的数据库中的行中。

感谢。

3 个答案:

答案 0 :(得分:2)

好吧,我会把我的形状结构有点不同,所以你把成分组装成他们自己的阵列,但是你得到了结果:

$db = new PDO($dsn, $user, $pass);

$stmt = $db->prepare('INSERT INTO ingredient (name, quantity) VALUES (?,?)');

// youll want to verify that both arrays have the same number of elements before doing this
// as part of your validation 
$ingredients = array_combine($_POST['recipe']['ingredient'], $_POST['recipe']['quantity']);

$errors = array();

foreach($ingredients as $name => $quantity)
{
    try {
       $stmt->execute(array($name, $quantity));
    } catch (PDOException $e) {
       $errors[] = array(
          'message' => "Could not insert \"$name\", \"$quantity\".",
          'error' => $e
    }    
}

if(!empty($errors)) {
   //do something?
}

答案 1 :(得分:1)

没有错误检查的简单示例:

<?php

    $dbc = new PDO(/* ... */);

    $stmt = $dbc->prepare("INSERT INTO tbl(ingredient,quantity) VALUES(:ingredient,:quantity);");
    $numIngredients = count($_POST['recipe']['ingredient']);
    for ($i=1; $i <= $numIngredients; $i++) { 
        $stmt->execute(array(
            ':ingredient' => $_POST['recipe']['ingredient'][$i],
            ':quantity'   => $_POST['recipe']['quantity'][$i]
        ));
    }

?>

请注意,通常您应该从0开始计算索引,如果您只是编写recipe[ingredient][],PHP将自动创建索引。

答案 2 :(得分:0)

我认为您的问题是$_POST数组的格式。你有:

[recipe][ingredient][...] and
[recipe][quantity][...]

但是,这不是数据库的结构,它按行和列组织它:

[recipe][...][ingredient, quantity]

您可以看到[...]如何移动。您需要数组格式映射到数据库格式。使用foreach

最简单
$recipes = array(); # Zero rows to insert we start with.
$formRecipes = $_POST['recipe']; # The form recipes are located here.

# The [...] part is in ingredient:
foreach ($formRecipes['ingredient'] as $index => $ingredient)
{
    # the [...] part is $index now
    $recipes[$index]['ingredient'] = $ingredient;       
    $recipes[$index]['quantity'] = $formRecipes['quantity'][$index];
}

运行完毕后,使用print_r验证一切正常:

print_r($recipes);

您现在可以使用$recipes数组将数据插入到每行的数据库中(我假设您知道如何执行插入SQL查询,因此我不会将其放入答案中)。