下面的脚本可以正常使用Firefox和Chrome但我似乎无法使用它,即尝试了所有内容甚至降低了浏览器的安全性,看看是否阻止它,但我仍然无法让它工作
function postData() {
var http = new XMLHttpRequest();
var url = "/scripts/remove_fr.php";
var params = "";
http.open("GET", url, true);
//Send the proper header information along with the request
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.setRequestHeader("Content-length", params.length);
http.setRequestHeader("Connection", "close");
http.onreadystatechange = function() { //Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
}
}
http.send(params);
}
$("#qwerty").click(function () {
$('#qwerty').remove();
});
</script>
答案 0 :(得分:6)
在IE7下面,它使用ActiveXObject
个对象而不是XMLHttpRequest
所以你的代码应该是这样的:
function postData() {
var http;
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
http = new XMLHttpRequest();
}
else {
// code for IE6, IE5
http = new ActiveXObject("Microsoft.XMLHTTP");
}
var url = "/scripts/remove_fr.php";
var params = "";
http.open("GET", url, true);
//Send the proper header information along with the request
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.setRequestHeader("Content-length", params.length);
http.setRequestHeader("Connection", "close");
http.onreadystatechange = function() { //Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
}
}
http.send(params);
}
答案 1 :(得分:2)
您可以尝试使用此代码,这会根据浏览器获取XMLHttpRequest。
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
请参阅链接了解详情w3schools
答案 2 :(得分:1)
您已经在使用jQuery了,所以请使用jQuery's AJAX utility functions!不要试图自己动手; XMLHttpRequest API很丑陋而烦人。
我想提供示例代码,但是现在你所拥有的只是:
$.get("/scripts/remove_fr.php");
这不是一个例子。 ;)