Question

当我在2上调用+时，我得到一个Int，但是当使用显式方法调用完成时，我得到了Double。

scala> 2+2
res1: Int = 4

scala> 2.+(2)
res2: Double = 4.0

似乎。在隐式转换的Int到Double上调用。+（）。

scala> 2.+
<console>:16: error: ambiguous reference to overloaded definition,
both method + in class Double of type (x: Char)Double
and  method + in class Double of type (x: Short)Double
match expected type ?
              2.+
                ^

为什么会这样？

Answer 1

在Scala 2.9及之前，2.被解释为2.0，因此模糊点表示浮点文字。您可以使用语法(2).+(2)显式调用该方法。

然而，不明确的浮点语法将在2.10中弃用：

scala> 2.+(2)
<console>:1: warning: This lexical syntax is deprecated.  From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
       2.+(2)
       ^
<console>:2: warning: This lexical syntax is deprecated.  From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
              2.+(2)
              ^
<console>:8: warning: This lexical syntax is deprecated.  From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
              2.+(2)
              ^
res1: Double = 4.0

Answer 2

原因不在于显式方法调用 - 通过编写2.+，在左侧指定Double，然后在其上调用加法运算符：

scala> 2.
res0: Double = 2.0

Scala运算符奇怪

2 个答案: