我有3张桌子。 电影院,预订和客户
create table cinema
(
c_id int,
location varchar(10)
)
insert into cinema values(1,'New York');
insert into cinema values(2,'London');
insert into cinema values(3,'Paris');
create table booking
(
c_id int,
cust_id int
)
insert into booking values(1,10);
insert into booking values(2,11);
insert into booking values(3,12);
insert into booking values(3,13);
insert into booking values(2,14);
create table customer
(
cust_id int,
cust_name varchar(10)
)
insert into customer values(10,'sam');
insert into customer values(11,'adrian');
insert into customer values(12,'mark');
insert into customer values(13,'jim');
insert into customer values(14,'tom');
我想选择未在巴黎预订的所有客户的客户ID(即; cust_id),客户名称(cust_name)和位置(来自电影院表)。
我想要的是 -
cust_id cust_name location
10 sam New York
11 adrian London
14 tom London
我尝试了很多...... 我的一个代码是---
SELECT customer.cust_id,customer.cust_name,
cinema.location as Location FROM booking,cinema,customer
WHERE booking.c_id=cinema.c_id AND location!='Paris';
它给了我15个结果.. 我想不出怎么做.. 请帮帮我。
答案 0 :(得分:4)
在您的代码中,您没有加入booking
到customer
,这会导致您的问题。我使用显式连接而不是隐式连接。虽然没有difference,但显式语法是标准的。
select cu.cust_id, cu.cust_name, ci.location
from cinema ci
join booking b
on ci.c_id = b.c_id
join customer cu
on b.cust_id = cu.cust_id
where ci.location <> 'Paris'
我不完全确定您的预订表的结构。我期待更多的列,例如门票数量等。
答案 1 :(得分:3)
您的WHERE statement
并不像您想要的那样具体。
您需要符合booking.cust_id to customer.cust_id
的条件:
WHERE booking.c_id = cinema.c_id
AND booking.cust_id = customer.cust_id
AND location != 'Paris'
现在,您正在为所有客户组合制定结果。
答案 2 :(得分:0)
见下面的例子:
Select
businessuser.UserName,
businessuser.EmailAddress,
businessimages.ImgName,
featured_cart.FeaturedPlan,featured_cart.StartDate
From featured_cart
Inner Join businessimages on featured_cart.FeaturedProId = businessimages.IdBusinessImages
Inner Join businessuser on businessimages.UserId = businessuser.IdBusinessUser
and featured_cart.FeaturedType = "Featured Email"
3个表是:
这个例子正常工作......
答案 3 :(得分:0)
MS SQL Server 2008:
select cust_id, cust_name, location
from customer c
inner join booking b
inner join location l
on c.cust_id = b.cust_id and b.c_id=l.c_id
答案 4 :(得分:0)
复合加入加入四个表:
使用了4个表
此示例100%工作您可以在W3schools中尝试此操作 - 内部加入“尝试自己”SQL编辑器表格取自W3schools编辑器。
<强> QUERY:强>
Select Customers.CustomerName as Table1_Customer, Orders.EmployeeID as Table2_Employee, OrderDetails.Quantity as Table3_OrderDetails,Products.ProductName as Table4_Products
From Customers
INNER JOIN Orders
ON Customers.CustomerID = Orders.CustomerID
INNER JOIN OrderDetails
ON Orders.OrderID = OrderDetails.OrderID
INNER JOIN Products
ON OrderDetails.ProductID = Products.ProductID Order by EmployeeID;
答案 5 :(得分:0)
你可以使用这样的连接:
<强> SQL 强>
select customer.cust_id,customer.cust_name,cinema.location from cinema,customer,booking where cinema.c_id=booking.c_id and booking.cust_id=customer.cust_id and cinema.location not like 'paris';