Question

我正在创建一个“忘记密码”页面，用户输入其电子邮件地址，脚本会找到与该电子邮件关联的密码，并将其发送到存储的电子邮件地址。

我认为问题与我的SMTP邮件服务器有关。我使用的WAMP没有，所以我下载了一个免费的。

这是我正在使用的php脚本：

    $id = checkEmail($email);
    $record = readMemberRecord($id);
    $password = @mysql_result($record,0,'cred');

    if($password){
        $email_subject = "Email Request";
        $email_body = "Your password is ".$password.".";
        $header = "NinjaMan";
        mail($email, $email_subject, $email_body,$header);
        $msg = "Your password has been sent to ".$email.".";
    }else{
        $msg = "Sorry, the email ".$email." wasn't found.";
    }

$ msg输出正确，所以我知道代码正在传递邮件功能。

Answer 1

尝试在$header中发送正确的“发件人”。

$emailFrom = "admin@yourdomain.com"; // match this to the domain you are sending email from
$email = "example@example.com";
$subject = "Email Request";
$headers = 'From:' . $emailFrom . "\r\n";
$headers .= "Reply-To: " . $email . "\r\n";
$headers .= "Return-path: " . $email;
$message = "Your password is ".$password.".";
mail($email, $subject, $message, $headers);

查看mail() function。

的详细信息

如果这不起作用，请尝试使用PHPMailer。您可以在代码中配置它，无需编辑php.ini。

我在一些项目中使用它（v 2.0.4，我看到最新的是5.1）并且没有问题。

Answer 2

尝试使用Google的服务器发送邮件，您可以看到如何执行此操作here

Answer 3

尝试使用此

//Email information
$to = "garggarima@gmail.com";
$subject = "Test mail";
$message = "Hello! This is a test email message.";
$from = "support@sltechsoft.com";
$headers = "From:" . $from;

$mail=mail($to,$subject,$message,$headers);
if($mail) {
    echo "Thanks for mail";
} else {
    echo "Mail not Sent";
}

//Email response
echo "Thank you for contacting us!";

警告：mail（）[function.mail]：SMTP服务器响应：550收件人无效：

3 个答案: