Question

我不想成为村里的白痴，但我不知道Linq对XML的运作方式。我知道它应该像编写SQL查询一样，但我无法绕过它。我试图从XML字符串中获取数据。我不想使用XMLDocuments和XPath来执行此操作。我能做到这一点，我做到了，我试图让我的应用程序更时髦。我拥有的XML有点繁琐，但我能够使用Xpath来解析它。 Linq to XML应该更容易。从以下XML我需要获取所有元素并将它们绑定到POCO对象。例如，我需要使用具有PatientID name属性的元素节点的value属性（4563）设置Patient.PatientId对象。现在，我可以使用XmlDocument了解如何执行此操作。但我不能为我的生活弄清楚如何用LINQ to XML做到这一点？我能做什么？我有一个例子，说明我试图在xml下面做的事情给我带来麻烦。

<?xml version="1.0" encoding="utf-8"?>
<dataTemplateSpecification id="id1" name="name1" >
  <templates xmlns="">
    <template>
      <elements>
        <element id="element0" name="PatientId" display="Patient ID" dataType="String" visable="true" readOnly="false" value="4563">
          <mapping path="//Template/TemplateData/ACOData/PATIENT_ID" />
          <validation>
            <rules>
              <rule id="r0" test="#element0.value == ''">
                <fail>
                  <html>
                    <b>Patient ID is null, value must be present</b>
                  </html>
                </fail>
              </rule>
            </rules>
          </validation>
        </element>
        <element id="element1" name="PopulationPatientID" display="Population Patient ID" dataType="String" visable="true" readOnly="true" enc="2098" value="6407">
          <mapping path="//Template/TemplateData/ACOData/POPULATION_PATIENT_ID" />
          <!--Patient/compositeID[./idType='populationPatientID']/id-->
          <validation>
            <rules>
              <rule id="r1" test="#element1.value == ''">
                <fail>
                  <html>
                    <b>EMPI ID is null, value must be present</b>
                  </html>
                </fail>
              </rule>
            </rules>
          </validation>
        </element>

同样，这是我尝试使用的LINQ to XML。

TemplateModel template = (TemplateModel)(from templates in elem.XPathSelectElements("//templates/template")
select new PatientACOData
{ 
       PatientId = templates.Elements("//element/element[@name='PatientId']").Attributes("value").Value;

});

UPDATE＆GT;＆GT;＆GT;上面的例子类定义很简单......简单......这是适当的类定义......

class PatientClass
{
    public int Item_ID { get; set; }
    public int PatientId { get; set; }
    public int EMPIID { get; set; }
    //public int PopulationPatientID { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public DateTime DateOfBirth { get; set; }
    public string Phone { get; set; }
    public string HostpitalFinNumber { get; set; }
    public DateTime AdminDate { get; set; }
    public string MRNType { get; set; }
    public string MRN { get; set; }
    public string PatientRoomPhone { get; set; }
    public DateTime DischargeDateTime { get; set; }
    public string DischargeDisposition { get; set; }
    public string DischargeTo { get; set; }
    public char DischargeAdvocateCall { get; set; }
    public string Payor { get; set; }
    public char HomeHealthCareAccepted { get; set; }
    public char SafeLandingAccepted { get; set; }
    public string PCPName { get; set; }
    public string PCPPhone { get; set; }
    public string SpecialistName { get; set; }
    public string SpecialistPhone { get; set; }
    public DateTime PCPAppointmentDateTime { get; set; }
    public string PCPAppointmentLocation { get; set; }
    public DateTime SpecialistAppointmentDateTime { get; set; }
    public string SpecialistAppointmentLocation { get; set; }
    public char CompletedPathway { get; set; }
    public string CompletedPathwayReason { get; set; }
    public string Comment { get; set; }
}

Answer 1

根据您的XML，我将填写PatientClass如下：

var xml = XElement.Load("XMLFile1.xml");

var patients = from template in xml.Element("templates").Elements("template")
                select new PatientClass
                {
                    PatientId = (from element in template.Element("elements").Elements("element")
                                where element.Attribute("name").Value == "PatientId"
                                select (int)element.Attribute("value")).FirstOrDefault()

                };

使用LINQ to XML从XML中获取值

1 个答案: