Question

我无法注册任何成就。我一直得到以下内容：

{"error":{"message":"(#3502) Object at achievement URL is not of type game.achievement","type":"OAuthException","code":3502}}

当我通过linter运行我的URL时，我得到：

Open Graph Warnings That Should Be Fixed

Inferred Property:  The 'og:url' property should be explicitly provided, even if a value can be inferred from other tags.
Inferred Property:  The 'og:title' property should be explicitly provided, even if a value can be inferred from other tags.

虽然当我自己加载URL时，我清楚地看到了meta标签中的设置。我的HTML看起来像：

<html>
<head prefix="og: http://ogp.me/ns# fb: http://ogp.me/ns/fb# game: http://ogp.me/ns/game#">
  <meta property="fb:app_id"      content="<MY_APP_ID>" /> 
  <meta property="og:type"        content="game.achievement" /> 
  <meta property="og:url"         content="http://<MY_DOMAIN>/ach10.html" /> 
  <meta property="og:title"       content="Title" /> 
  <meta property="og:description" content="Description" /> 
  <meta property="og:image"       content="http://placekitten.com/g/200/300" />
</head>
<body>
Hmm..
</body>
</html>

同样有趣的是，图API将其视为：

{
   "url": "http://<MY_DOMAIN>/ach10.html",
   "type": "website",
   "title": "http://<MY_DOMAIN>/ach10.html",
   "updated_time": "2012-03-09T19:49:14+0000",
   "id": "<ID>"
}

抓取的网址没有返回任何内容......任何人都有任何想法？我还尝试在Open Graph设置中添加Game Achievement对象，并启用和禁用Sandbox Mode / Social Discovery的每个组合。

Answer 1

你必须包括游戏：积分元标记来完成你的游戏。快乐

无法注册成就

1 个答案: