我有一个文本框,当它有焦点时,它下面会出现一个弹出窗口。但是当弹出窗口打开并滚动时,它似乎停留在打开它的同一位置。当我滚动时,我需要帮助弄清楚如何让弹出窗口出现在文本框下方。我将如何在xaml中执行此操作?
谢谢!
MainWindow查看:
<Grid x:Name="LayoutRoot">
<ScrollViewer>
<local:ControlView/>
</ScrollViewer>
</Grid>
资源词典:
<Style TargetType="{x:Type Popup}">
<Style.Triggers>
<DataTrigger Binding="{Binding ElementName=txtTest, Path=IsKeyboardFocused}" Value="True">
<Setter Property="IsOpen" Value="True" />
</DataTrigger>
<DataTrigger Binding="{Binding ElementName=txtTest, Path=IsKeyboardFocused }" Value="False">
<Setter Property="IsOpen" Value="False" />
</DataTrigger>
</Style.Triggers>
</Style>
<Style x:Key="BorderStyle" TargetType="{x:Type Border}">
<Setter Property="Background" Value="LemonChiffon"/>
<Setter Property="Padding" Value="5"/>
</Style>
UserControl查看:
<Grid x:Name="LayoutRoot">
<StackPanel Grid.Row="1" Grid.Column="4" Orientation="Vertical">
<Button Content="Button" Width="100" Height="100"/>
<Button Content="Button" Width="100" Height="100"/>
<TextBox x:Name="txtTest" HorizontalAlignment="Stretch"/>
<Popup Name="TestPopup" StaysOpen="True"
PlacementTarget="{Binding ElementName=txtTest}"
AllowsTransparency="True" Placement="{Binding ElementName=txtTest}">
<Border Style="{DynamicResource BorderStyle}">
<GroupBox Header="Test Popup">
<ScrollViewer Margin="0,2,0,0" VerticalScrollBarVisibility="Hidden">
<!--BINDING-->
<Label Content="Hello World!"/>
</ScrollViewer>
</GroupBox>
</Border>
</Popup>
<ContentPresenter Content="{Binding testBinding}"
VerticalAlignment="Stretch" HorizontalAlignment="Stretch">
</ContentPresenter>
</StackPanel>
</Grid>
答案 0 :(得分:1)
试试这个:
<Style TargetType="{x:Type Popup}">
<Setter
Property="IsOpen"
Value="{Binding IsKeyboardFocusedWithin, ElementName=txtTest, Mode=OneWay}"/>
</Style>