Question

我需要在子线程中使用弹出窗口。看一下示例代码的各种片段，我得到了以下内容：

void completed_dialog()
{
  dialog_action_taken = false;

  runOnUiThread(new Runnable()
  {
    public void run()
    {
      Button but = (Button) findViewById(R.id.pop_can);
      LayoutInflater inflater = (LayoutInflater)
      getSystemService(Context.LAYOUT_INFLATER_SERVICE);
      final PopupWindow pw = new PopupWindow(inflater.inflate(R.layout.endofgame,
           null, false), 300, 300,  true);
      pw.setBackgroundDrawable(new BitmapDrawable());
      OnClickListener cancel_button_click_listener = new OnClickListener() 
      {
        public void onClick(View v) 
        {
          pw.dismiss();
        }
      };
      but.setOnClickListener(cancel_button_click_listener);
      pw.showAtLocation(game_frame_layout, Gravity.CENTER, 0, 0);
   }
  }
}

如果行“but.setOnClickListener（cancel_button_click_listener）;”被注释掉然后我完全看到了对话框和按钮。但是如果我离开该行，则程序在对话框应该出现的位置崩溃 - 即我从未看到对话框。我可以通过一个小的修改来使代码工作吗？

Answer 1

你的findViewById()找不到按钮。你需要让它看起来像这样的布局

public void run()
{
  LayoutInflater inflater = (LayoutInflater)
  getSystemService(Context.LAYOUT_INFLATER_SERVICE);
  View layout = inflater.inflate(R.layout.endofgame, null, false);
  Button but = (Button) layout.findViewById(R.id.pop_can);
  final PopupWindow pw = new PopupWindow(layout, 300, 300,  true);
  pw.setBackgroundDrawable(new BitmapDrawable());
  OnClickListener cancel_button_click_listener = new OnClickListener() 
  {
    public void onClick(View v) 
    {
      pw.dismiss();
    }
  };
  but.setOnClickListener(cancel_button_click_listener);
  pw.showAtLocation(game_frame_layout, Gravity.CENTER, 0, 0);
}

在子线程内的自定义弹出窗口中设置onclicklistener

1 个答案: