Question

好的，我有一张表格

<form  action="/search" method="post">
<input type="hidden" name="location_id" value="1" /><br />
<input class='small' data-datepicker='datepicker' name='start_date' type='text' value='03-09-2012'>
<input class='small' data-datepicker='datepicker' name='end_date' type='text' value='03-09-2012'>
</form>

我有路线

 match "/search", :to => "locations#search"

并在我的控制器中

def search
  @location = Location.find(params[:location_id])
  start_date = DateTime.strptime(params[:start_date], "%m-%d-%Y")
  end_date = DateTime.strptime(params[:end_date], "%m-%d-%Y")
  @songs = @location.songs.paginate(:page => params[:page], :per_page => 30, :conditions => {:play_date => start_date..end_date})
  render 'show'
end

当我点击第2页或下一页页面错误时，所有的作品都很完美，因为我没有在params中的location_id或日期....任何关于如何解决这个问题的想法...我正在使用will_paginate宝石

错误

Couldn't find Location without an ID

参数：

{"page"=>"2"}

Answer 1

您需要将location_id参数添加到您的will_paginate视图助手中，如下所示：

<%= will_paginate @some_objects, :params=>{:location_id=>@location.id} %>

希望它有所帮助。

Rails搜索，页面下一页点击失败

1 个答案: