Question

我的数据库有3行（并非列出所有列）：

**uFirst** | **uApp** 
  Dave     | approved
  John     | declined
  Jane     | no

此SQL正在运行，并显示所有行：

SELECT u.uID, u.uManT, u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN', m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep, u.uRepd, u.uManT, u.uStatus, u.uManR 
          FROM users AS u LEFT OUTER JOIN users AS m
          ON u.uManT = m.uID 
          WHERE u.uManR = " . $luID . " 
          AND u.uStatus = 'Physician' 
          ORDER BY u.uLast ASC";

当我尝试添加COUNT时，它只显示1行（已批准的行）：

SELECT COUNT(CASE WHEN u.uApp = 'approved' THEN 1 END) AS Approved, 
       COUNT(CASE WHEN u.uApp = 'declined' THEN 1 END) AS Declined, 
       u.uID, u.uManT, u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN', m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep, u.uRepd, u.uManT, u.uStatus, u.uManR 
          FROM users AS u LEFT OUTER JOIN users AS m
          ON u.uManT = m.uID 
          WHERE u.uManR = " . $luID . " 
          AND u.uStatus = 'Physician' 
          ORDER BY u.uLast ASC";

我正在尝试显示所有行，以及已批准的用户数。我做错了什么？

Answer 1

在这种情况下只返回1行，因为你没有使用GROUP BY，这个查询可以得到你想要的东西：

SELECT COUNT(uFirst) AS Total, u.uID, u.uManT, 
     u.uFirst AS 'NomFN', m.uFirst AS 'ManFN', u.uLast AS 'NomLN',
     m.uLast AS 'ManLN', u.uNomd, u.uApp, u.uApp, u.uAppd, u.uRep,
     u.uRepd, u.uManT, u.uStatus, u.uManR 
FROM users AS u 
LEFT OUTER JOIN users AS m ON u.uManT = m.uID 
WHERE u.uManR = " . $luID . " AND u.uStatus = 'Physician' 
GROUP BY uApp
ORDER BY u.uLast ASC";

将COUNT（和限定符）添加到SQL语句

1 个答案: