Question

好的，所以我正在尝试解析Foursquare返回的数据，以获取GET请求以返回场地详细信息。以下是我需要解析的响应部分：

{"meta":{"code":200,"errorType":"deprecated","errorDetail":"Please provide an API version to avoid future errors.See http:\/\/bit.ly\/vywCav"},"response":{"venue":{"id":"4b522afaf964a5200b6d27e3","name":"The Woodville","contact":{"phone":"+442920397859","formattedPhone":"+44 29 2039 7859","twitter":"woodvillelovers"},"location":{"address":"1 - 5 Woodville Rd.","lat":51.49051570871893,"lng":-3.1805795431137085,"postalCode":"CF24 4DW","city":"Cardiff","state":"Wales","country":"United Kingdom"}

这是我解析和显示此信息的代码：

$json = json_decode($response);
foreach ($json->response->venue as $result)
{
    echo $result->name.' - '.$result->address.' '.$result->city."<p />";
 }

我得到的错误是foreach中的行是'试图获取非对象的属性'。我在这做错了什么？似乎无法看到问题。提前谢谢。

Answer 1

这只是一个猜测，因为我不知道php，但可能是因为地址和城市不属于场地，而是位于场地 - >位置。

$json = json_decode($response);
foreach ($json->response->venue as $result)
{
    echo $result->name.' - '.$result->location->address.' '.$result->location->city."<p />";
 }

如何解析Foursquare返回的JSON

1 个答案: