我想在按两次keypad_hash时显示下一个表达式。
目前我能做的是:
如果我的观察是正确的,那么第一个IF站中的“click = 1”没有做任何事情。
if ("2+3=5".equals(display.getText().toString()))
{
correct.setText("CORRECT");
click=1;
}
有什么建议吗?
package org.example.question;
import java.util.Random;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
public class QuestionActivity extends Activity implements View.OnClickListener {
/** Called when the activity is first created. */
//variable for different questions
int fnum0, snum0,fnum1, snum1,fnum2, snum2,fnum3, snum3,
fnum4, snum4,fnum5, snum5,fnum6, snum6,fnum7, snum7,
fnum8, snum8,fnum9, snum9, answer;
//variable and type declaration for buttons and text
Button keyOne;
Button keyTwo;
Button keyThree;
Button keyFour;
Button keyFive;
Button keySix;
Button keySeven;
Button keyEight;
Button keyNine;
Button keyDel;
Button keyZero;
Button keyHash;
Button keySubtract;
TextView display;
TextView display1;
TextView correct;
TextView Incorrect;
int q=0;
int click=0;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
//display text on screen
display1 = (TextView)findViewById(R.id.Guess);
display = (TextView)findViewById(R.id.Title);
correct= (TextView)findViewById(R.id.CORRECT);
Incorrect= (TextView)findViewById(R.id.INCORRECT);
//assigning names to each keypad
keyOne= (Button) findViewById(R.id.keypad_1);
keyTwo= (Button) findViewById(R.id.keypad_2);
keyThree= (Button) findViewById(R.id.keypad_3);
keyFour= (Button) findViewById(R.id.keypad_4);
keyFive = (Button) findViewById(R.id.keypad_5);
keySix= (Button) findViewById(R.id.keypad_6);
keySeven = (Button) findViewById(R.id.keypad_7);
keyEight = (Button) findViewById(R.id.keypad_8);
keyNine = (Button) findViewById(R.id.keypad_9);
keyZero = (Button) findViewById(R.id.keypad_0);
keySubtract = (Button) findViewById(R.id.keypad_subtract);
keyHash = (Button) findViewById(R.id.keypad_hash);
keyDel = (Button) findViewById(R.id.delete);
//setting button to produce an event when each button is pressed
keyOne.setOnClickListener(this); keyTwo.setOnClickListener(this); keyThree.setOnClickListener(this);
keyFour.setOnClickListener(this); keyFive.setOnClickListener(this); keySix.setOnClickListener(this);
keySeven.setOnClickListener(this); keyEight.setOnClickListener(this); keyNine.setOnClickListener(this);
keySubtract.setOnClickListener(this); keyHash.setOnClickListener(this); keyDel.setOnClickListener(this);
}
public void onClick(View arg0) {
//created a new string object
String str=new String();
int click=0;
int q=0;
switch(arg0.getId()){
//what happens when hash button is pressed
case R.id.keypad_hash:
if ("2+3=5".equals(display.getText().toString()))
{
correct.setText("CORRECT");
click=1;
}
else if (click==1 && q==1 && "CORRECT".equals(display1.getText().toString()))
{
fnum0=(int) ((double) ((Math.random() * 10)));
snum0=(int) ((double) ((Math.random() * 10)));
int operation = (int) ((double) ((Math.random() * 10 )));
if(operation == 0)
str = fnum0+ "+" + snum0+ "=" + ((fnum0+snum0<10)? "?" : "??");
else if(operation == 1)
str = fnum0+ "-" + snum0+ "=" + ((fnum0+snum0<10)? "?" : "??");
else if(operation == 2)
str = fnum0+ "*" + snum0+ "=" + ((fnum0+snum0<10)? "?" : "??");
else if(operation == 0)
str = fnum0+ "/" + snum0+ "=" + ((fnum0+snum0<10)? "?" : "??");
display.setText(str);
display.setText(fnum0+"+"+snum0+"=");
click=2;
}
case R.id.keypad_1:
String str1 = display.getText().toString();
display.setText(str1.replace("?", "1"));
break;
case R.id.keypad_2:
String str2 = display.getText().toString();
display.setText(str2.replace("?", "2"));
break;
case R.id.keypad_3:
String str3 = display.getText().toString();
display.setText(str3.replace("?", "3"));
break;
case R.id.keypad_4:
String str4 = display.getText().toString();
display.setText(str4.replace("?", "4"));
break;
case R.id.keypad_5:
String str5 = display.getText().toString();
display.setText(str5.replace("?", "5"));
break;
case R.id.keypad_6:
String str6 = display.getText().toString();
display.setText(str6.replace("?", "6"));
break;
case R.id.keypad_7:
String str7 = display.getText().toString();
display.setText(str7.replace("?", "7"));
break;
case R.id.keypad_8:
String str8 = display.getText().toString();
display.setText(str8.replace("?", "8"));
break;
case R.id.keypad_9:
String str9 = display.getText().toString();
display.setText(str9.replace("?", "9"));
break;
case R.id.keypad_0:
String str0 = display.getText().toString();
display.setText(str0.replace("?", "0"));
break;
case R.id.keypad_subtract:
display.setText("-");
break;
}
}
public void requestFocus() {
// TODO Auto-generated method stub
}
}
答案 0 :(得分:0)
您每按一次按钮就会创建一个新的特定方法click
。
public void onClick(View arg0) {
//created a new string object
String str=new String();
int click=0; /// <---- here
int q=0;
这是引用的内容,在方法调用之间永远不会增加。