我的应用程序运行的服务每小时发送一次通知。由于我的通知,我每小时都听到声音和振动,但工作正常,但我也希望我的通知也会点亮我的屏幕。但是,当出现通知时,我无法点亮我的屏幕。
答案 0 :(得分:46)
PowerManager pm = (PowerManager)context.getSystemService(Context.POWER_SERVICE);
boolean isScreenOn = pm.isScreenOn();
Log.e("screen on.................................", ""+isScreenOn);
if(isScreenOn==false)
{
WakeLock wl = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK |PowerManager.ACQUIRE_CAUSES_WAKEUP |PowerManager.ON_AFTER_RELEASE,"MyLock");
wl.acquire(10000);
WakeLock wl_cpu = pm.newWakeLock(PowerManager.PARTIAL_WAKE_LOCK,"MyCpuLock");
wl_cpu.acquire(10000);
}
答案 1 :(得分:1)
有我的解决方案:
createNotification(); //your implementation
PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
boolean isScreenOn = Build.VERSION.SDK_INT >= 20 ? pm.isInteractive() : pm.isScreenOn(); // check if screen is on
if (!isScreenOn) {
PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.SCREEN_DIM_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP, "myApp:notificationLock");
wl.acquire(3000); //set your time in milliseconds
}
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