Question

我正在编写一份报告，需要显示一周的收据，按地点分组，每周的每一天都有一个单独的列。这将通过SSRS和SQL Server 2008 R2提供。最终结果应如下所示:(但对于一周中的所有7天）

Location    Monday    Tuesday
Building3   $100      $75
Building4   $25       $35
Building5   $105      $21

我编写了以下T-SQL SELECT语句，以便从我的报表变量（@reporting）中获取此数据。然后打算按位置对输出进行分组，以获得上面显示的布局。

原始数据列出了单行中的收货日期，总计和位置。我想转动数据，以便星期几显示在最前面。必须有一个比你在下面看到的更好的方法。有帮助吗？

    SELECT
        LocationKey.Location
        ,Sunday.Cost as Sunday
        ,Monday.Cost as Monday
    FROM 

        (
            SELECT DISTINCT Location 
            FROM @reporting
            WHERE Location NOT IN ('Building01', 'Building02', '')
        ) AS LocationKey

    LEFT JOIN  

(SELECT  

sunday.Location
,sunday.Cost

FROM @reporting as sunday (nolock) 

WHERE DATEPART(weekday,sunday.ReceiptDate)= 1

        ) AS Sunday
        ON Sunday.Location = LocationKey.Location

LEFT JOIN  

(SELECT  
Monday.Location,
Monday.Cost

FROM @reporting as Monday (nolock) 

WHERE DATEPART(weekday,Monday.ReceiptDate)= 2

        ) AS Monday
        ON Monday.Location = LocationKey.Location

Answer 1

执行此操作的最简单方法可能是PIVOT上的DATENAME。

SELECT location, 
       [Saturday], 
       [Sunday], 
       [Monday], 
       [Tuesday], 
       [Wednesday], 
       [Thursday], 
       [Friday] 
FROM   (SELECT COST, 
               location, 
               Datename(weekday, receiptdate) DAY 
        FROM   @reporting 
        WHERE  location NOT IN ( 'Building01', 'Building02', '' )) p 
      PIVOT ( 
        SUM (COST) 
        FOR DAY IN ( [Saturday], [Sunday], [Monday], [Tuesday], [Wednesday], 
       [Thursday], [Friday]) ) pvt

请参阅此data.se query

另一种方法是使用多个自连接但不使用子查询。这里的关键是Join Clause

SELECT LocationKey.Location,
       SUM(Sunday.Cost) As [Sunday],
       SUM(Monday.Cost) As [Monday],
       SUM(Tuesday.Cost) As [Tuesday],
       SUM(Wednesday.Cost) As [Wednesday],
       SUM(Thursday.Cost) As [Thursday],
       SUM(Friday.Cost) As [Friday],
       SUM(Saturday.Cost) As [Saturday]
FROM
      (SELECT DISTINCT Location 
            FROM @reporting
            WHERE Location NOT IN ('Building01', 'Building02', '')) LocationKey
      LEFT JOIN @Reporting Sunday 
      ON LocationKey.Location = Sunday.Location
         AND DATEPART(weekday,sunday.ReceiptDate)= 1
      LEFT JOIN @Reporting Monday
      ON LocationKey.Location = Monday.Location
         AND DATEPART(weekday,Monday.ReceiptDate)= 2
      LEFT JOIN @Reporting Tuesday
      ON LocationKey.Location = Tuesday.Location
         AND DATEPART(weekday,Tuesday.ReceiptDate)= 3
      LEFT JOIN @Reporting Wednesday
      ON LocationKey.Location = Wednesday.Location
         AND DATEPART(weekday,Wednesday.ReceiptDate)= 4
      LEFT JOIN @Reporting Thursday
      ON LocationKey.Location = Thursday.Location
         AND DATEPART(weekday,Thursday.ReceiptDate)= 5
      LEFT JOIN @Reporting Friday
      ON LocationKey.Location = Friday.Location
         AND DATEPART(weekday,Friday.ReceiptDate)= 6         
      LEFT JOIN @Reporting Saturday
      ON LocationKey.Location = Saturday.Location
         AND DATEPART(weekday,Saturday.ReceiptDate)= 7

您应该注意，您应该拨打SET DATEFIRST或使用@@DATEFIRST的偏移量来保护您的查询免受默认设置的影响，当您使用DATEPART(weekday..时更改并破坏您的查询

Answer 2

此PIVOT查询可以为您提供所需内容：

select Location, Cost_D1, Cost_D2, Cost_D3, Cost_D4, Cost_D5, Cost_D6, Cost_D7
from (
    select Location, 'Cost_D' + convert(varchar,datepart(weekday,ReceiptDate)) as FieldName, Cost
    from @reporting
) s
pivot
(
    sum(Cost)
    for FieldName
    in (Cost_D1, Cost_D2, Cost_D3, Cost_D4, Cost_D5, Cost_D6, Cost_D7)
) p

TSQL报告 - 按周计算数据？

2 个答案: