我可以制作这样的功能:
def again ():
again = input ( "want to input the word again ? yes =1 no =2 ")
if again == 1:
func_input_word()
else:
return keuzemaken
答案 0 :(得分:3)
我猜这段代码会做你想要的:
def func_input_word():
input_word = ""
while len(input_word) < 6:
input_word = input("Input a 6 letter word: ")
if len(input_word) < 6:
print("Too small, try again!")
else:
return input_word
def option(my_choose): #function named: make choose ( choice )
if my_choose == 1:
input_word = func_input_word()
else:
....
答案 1 :(得分:1)
这个怎么样:
def option(my_choose): #function named: make choose ( choice )
if my_choose == 1:
while len(input_word) < 6:
input_word = input( "type het gekozen 6 letterig woord in : ") #input for word
if len(input_word) < 6:
print ("to short, try again ")
else:
break
else:
....