Question

是否有可能在matplotlib中重新打开一个封闭的数字（即用户X'd）？以下代码显示了天真的方法：

In [14]: fig = figure(10)

In [15]: close(fig)

In [16]: fig.show()

Exception in Tkinter callback
Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/lib-tk/Tkinter.py", line 1410, in __call__
    return self.func(*args)
  File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/lib-tk/Tkinter.py", line 495, in callit
    func(*args)
  File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/matplotlib/backends/backend_tkagg.py", line 253, in idle_draw
    self.draw()
  File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/matplotlib/backends/backend_tkagg.py", line 239, in draw
    tkagg.blit(self._tkphoto, self.renderer._renderer, colormode=2)
  File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/matplotlib/backends/tkagg.py", line 19, in blit
    tk.call("PyAggImagePhoto", photoimage, id(aggimage), colormode, id(bbox_array))
TclError: this isn't a Tk application

我正在尝试创建一个带有小部件的图形，因此可以使用解决方法（只需创建一个新图形），但我想知道figure实例在关闭后是否完全没用。

Answer 1

是的，关闭数字会完全删除它。

Matplotlib：重新打开封闭的数字？

1 个答案: