Question

我有一些像这样的表：

予。父表：

id_client      id_group   package       start_date   end_date     id_contract   is_parent   
1223           88         1234          2012-01-01   2050-01-01   156447        1           
1223           89         34342         2011-04-01   2050-01-01   156447        1

II。分享表：

id        package      id_share
1         1234         SS4433  - parent
2         564679       SS4433  --- this is a child
3         564522       SS4433  -- this is a child 
4         34342        SS2345  - parent
5         665456       SS2345  -- child
6         7789997      SS2345  -- child

III。子表：

package       start_date   end_date      id_contract      

564679        2011-01-01   2012-02-01    156447
564522        2011-01-01   2011-05-07    156447
665456        2011-01-01   2012-02-04    156447
7789997       2011-01-01   2011-07-03    156447

问题是如何使用一个查询选择同一个选择中的父项及其所有子项（基于共享表中的id_share），其中包含父项的组。

结果应如下所示：

id_client      id_group      package         start_date  end_date    id_contract   child_of
1223           88            1234            2012-01-01  2050-..     156447        0
1223           88            564679          2011-01-01  2012-02-01  156447        1234
1223           89            34342           2011-04-01  2050-...    156447        0
1223           89            665456          2011-01-01  2012-02-04   156447        34342

我已经尝试过各种方式..但我无法弄清楚如何做到这一点......没有工会全部

我试过这个：

select a.id_client, a.id_group, ??package?? , id_contract , ??child_of??
from parent_table a 
join share_table b on b.package = a.package
join share_table c on c.id_share = b.id_share
join child_table d on d.package = c.package

PS：我需要找到对应于2012-01-01 - 2012-01-31间隔的父母和孩子

我放的地方？我不知道。

由于

Answer 1

更新，按日期限制父母和子女：

select a.id_client,
       a.id_group,
       coalesce(d.package, a.package) package,
       coalesce(d.start_date, a.start_date) start_date,
       coalesce(d.end_date, a.end_date) end_date,
       coalesce(d.id_contract, a.id_contract)  id_contract,
       case when d.package is not null then a.package else 0 end child_of
from parent_table a 
join share_table b on b.package = a.package
join share_table c on c.id_share = b.id_share
left join child_table d on d.package = c.package and
                           d.start_date <= '2012-01-31' and
                           d.end_date >= '2012-01-01' 
where a.start_date <= '2012-01-31' and
      a.end_date >= '2012-01-01' and
      (d.package is not null or a.package = c.package)

Answer 2

这个怎么样。

select p.id_client, p.id_group, s.package, c.start_date, c.id_contract
from parent p right outer join share s
on p.package = s.package
right outer join child c
on p.package = c.package;

Answer 3

联合似乎是一种更好的方法，但可以使用isnull和外连接...

select isnull(p.id_client, pofc.id_client) id_client, isnull(p.id_group, pofc.id_group) id_group, isnull(p.package, c.package) package, isnull(p.startDate, c.startDate), isnull(p.endDate, c.endDate) endDate, isnull(p.id_contract, c.id_contract) id_contract, isnull(pofc.package, 0) child_of  
from share s  
left outer join parent p on p.package = s.package  and p.startDate <= @toDate and p.endDate >= @fromDate  
left outer join child c on c.package = s.package and c.startDate <= @toDate and c.endDate >= @fromDate    
left outer join (select ps.id_share, p.package, p.id_client, p.id_group from share ps inner join parent p on p.package = ps.package) pofc on pofc.id_share = s.share and pofc.package <> s.package  
where p.package is not null  
  or c.package is not null

sql查询：连接的双记录...可以; t弄清楚

3 个答案: