Question

我正在使用LWUIT 1.5标签来显示通知。我有三个Tabs，我从php Web服务获取通知。我成功获取了第一个Tab的通知列表。但对于接下来的两个Tabs，我无法理解我应该写什么代码

检测到点击了第二个/第三个Tab。我知道如何将commandListener添加到Button。 commandListener选择的Tab是什么？

如何从服务器收到新数据时刷新Tab的内容？

private void showNotificationList（）{

try {

    Form f = new Form("Notifications");
    f.setScrollable(false);
    f.setLayout(new BorderLayout());
    final List list = new List(getNotifications()); //gets hashtables - notices
    list.setRenderer(new GenericListCellRenderer(createGenericRendererContainer(), createGenericRendererContainer()));
    list.setSmoothScrolling(true);
    //System.out.println("adding list component to listview");
    list.addActionListener(new ActionListener() {

        public void actionPerformed(ActionEvent evt) {
            int i = list.getSelectedIndex();
            noticeDetailsForm(notices[i]);
            //Dialog. show( "title",  notices[i].toString(),  "ok",  "exitt");
        }
    });
    //Container c2 = new Container(new BoxLayout(BoxLayout.Y_AXIS));
    //c2.addComponent(list);
    Tabs tabs = new Tabs(Tabs.TOP);
    tabs.addTab("Recent", list);
    tabs.addTab("Urgent", new Label("urgent goes here"));
    tabs.addTab("Favourites", new Label("favs goes here"));

    //f.addComponent(tabs);
    f.addComponent(BorderLayout.CENTER, tabs);
    Command backComm = new Command("Back") {

        public void actionPerformed(ActionEvent ev) {
            Dashboard.dbInstance.setUpDashboard();

        }
    };
    f.addCommand(backComm);
    //System.out.println("showing lsit form");
    f.show();
} catch (Exception ex) {
    ex.printStackTrace();
}

}

private Container createGenericRendererContainer() throws IOException { //System.out.println("container called");

//System.out.println("container called");
Container c = new Container(new BorderLayout());
c.setUIID("ListRenderer");

Label xname = new Label("");
Label description = new Label();
Label focus = new Label("");
Container cnt = new Container(new BoxLayout(BoxLayout.Y_AXIS));
xname.setName("Name");
xname.getStyle().setBgTransparency(0);
xname.getStyle().setFont(Font.createSystemFont(Font.FACE_SYSTEM, Font.STYLE_BOLD, Font.SIZE_MEDIUM));
//description.setFocusable(true);
description.setName("Description");
cnt.addComponent(xname);
cnt.addComponent(description);
c.addComponent(BorderLayout.CENTER, cnt);
Button thumb = new Button(Image.createImage("/res/home-work.png"));
//Image img = Image.createImage("/res/home-work.png");
c.addComponent(BorderLayout.WEST, thumb);

return c;

}

private Hashtable [] getNotifications（）{ int total = notices.length; //System.out.println(total）; Hashtable [] data = new Hashtable [total]; // Hashtable [] data = new Hashtable [5]; / data [0] = new Hashtable（）; data [0] .put（“Name”，“Shai”）; data [0] .put（“Surname”，“Almog”）; data [0] .put（“Selected”，Boolean.TRUE）; /

for (int i = 0; i < total; i++) {
    data[i] = new Hashtable();
    //System.out.println(notices[i].getName());
    data[i].put("Name", notices[i].getName());
    data[i].put("Description", notices[i].getDescription());
    data[i].put("Id", Integer.toString(notices[i].getId()));
}

return data;

}

Answer 1

1）我遇到了同样的问题，我通过覆盖Keyreleased的{{1}}而不是Form解决了这个问题在其中我检查了焦点的组件，如果是Tab获取“tab.selectedIndex”来检测我Tab我是谁并加载适当的数据。这是示例代码（这在我的派生形式中扩展了Form）

**

Tab

2）关于刷新数据我做了一个解决方案，我不知道它是否正确我获取新数据，创建新的public void keyReleased(int keyCode) { Component p=this.getFocused(); String str= p.getClass().getName(); if(str.toLowerCase().indexOf("radiobutton")!=-1){ // Radiobutton because when u Here do tab specific work focus on the tab it returns radiobutton. lwuit understands tabs as list of radiobuttons }**并删除旧数据然后附加新数据致电List;

LWUIT 1.5如何捕获标签点击事件，从服务器获取内容并在选定的标签中显示？

1 个答案: