我一直在尝试将这个程序编写好几个小时，所以请光临我。我甚至分别打破了循环，但是一旦我将所有东西放在一起，它就无法正常工作。
所以，让我分解我需要每个循环做什么，然后我得到什么输出：
1）我需要使用的第一个循环是do / while。在此循环中，提示用户键入单词。如果用户键入错误的单词，则会收到错误消息：
无效！再试一次！剩下2次尝试！
无效！再试一次！剩下1次尝试！
抱歉！你再也没有尝试了！
只要每次输入错误的单词，此输出就会起作用，但如果在尝试失败后输入了正确的单词，则仍会应用错误消息
2）在我的第二个循环（for循环）中，要求用户输入“3 * 8 =”如果输入错误的数字全部3次或者任何尝试都会输入24。
问题在于输入24后的循环。输出如下：
谢谢你等等。如果您是赢家，我们会致电5555555555。 3 * 8 = 不应显示3 * 8的情况。我意识到我可以休息一下;在此声明之后，但是说明具体说我不能使用break命令。
正确的输出应为：谢谢等等等等。如果您是胜利者，我们会致电5555555555。
public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
int attempt = 2;
int answer = 24;
long phoneNumber = 0;
String firstName = "";
String lastName = "";
String wordOfTheDay = "";
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if(wordOfTheDay.equals("tired"))
{
for( attempt = 2; attempt >= 0; --attempt)
{
System.out.print(" 3 * 8 = ");
answer = input.nextInt();
input.nextLine();
if( answer == 24)
{
System.out.printf( "Please enter your first name, last name, and phone number (no dashes or spaces)\n" +"in a drawing for an all-expenses-paid vacation in the Bahamas: " );
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
System.out.printf(
"Thank you %s %s. We'll call you at %d if you're a winner.",
firstName,
lastName,
+ phoneNumber);
}
else if( answer != 24)
{
if(attempt!=0)
{
System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
continue;
}
else
{
System.out.print( "Sorry! You have no more attempts left!" );
}
}
}
}
else
{
do
{
System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
--attempt;
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
} while (attempt >= 1);
if( attempt == 0)
{
System.out.print( "Sorry! You have no more attempts left!" );
}
}
}
我希望我说得够清楚。
总结一下，我需要用我的do /解决问题，而不是让我在尝试失败后输入正确的单词。
另外，我需要在用户输入正确的输入后摆脱3 * 8 =显示。
谢谢！
答案 0 :(得分：2)
我想你正试图这样做。！
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int answer = 0;
long phoneNumber = 0;
String firstName = "";
String lastName = "";
String wordOfTheDay = "";
int mainMenuAttempt = 3;
do {
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if (wordOfTheDay.equals("tired")) {
int answerAttempt = 3;
do {
System.out.print(" 3 * 8 = ");
answer = input.nextInt();
input.nextLine();
answerAttempt--;
if (answer != 24 && answerAttempt >0)
System.out.printf(
"Invalid! Try Again! %d attempt(s) left!\n ",
answerAttempt);
} while (answerAttempt >0 && answerAttempt < 3 && answer != 24);
if (answer == 24) {
System.out
.printf("Please enter your first name, last name, and phone number (no dashes or spaces)\n"
+ "in a drawing for an all-expenses-paid vacation in the Bahamas: ");
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
System.out
.printf("Thank you %s %s. We'll call you at %d if you're a winner.",
firstName, lastName, +phoneNumber);
}
}
mainMenuAttempt--;
} while (mainMenuAttempt >0 && mainMenuAttempt < 3 && !wordOfTheDay.equals("tired") && answer!=24);
System.exit(0);
}
}
答案 1 :(得分：2)
尝试将整个事情分解为非常小的函数，每个函数执行一个特定的事情。例如，您可能只有一个函数来检查单词是否正确，如果是，则返回0，如果不是则返回尝试次数。
private int checkWord(String correctWord, String wordToCheck, int attempts)
{
if(wordToCheck.equals(correctWord))
{
return 0;
}
return attempts;
}
然后您可以创建一个接受用户输入的函数，并调用此函数来检查所述输入。然后它可以输出一个错误消息，该消息取决于前一个函数的返回码。然后该函数将返回一个代码，告诉它上面的函数情况。
public int checkWordVerbose(String question, String correctWord, int attempts)
{
if(attempts <= 3)
{
Scanner scan = new Scanner(System.in);
System.out.print(question);
String input = scan.nextLine();
int failureCode = checkWord(correctWord, input, attempts);
if(failureCode == 0)
{
return 0;
}
else
{
System.out.println("Invalid! Attempts left: " + (3 - failureCode));
return 1;
}
}
else
{
System.out.println("Sorry! You have no more attempts left!\n");
return 2;
}
}
最后，你可以创建一个只包含循环的函数，并保存用于维护该循环的逻辑：
public int checkWord(String correctWord)
{
int failureCode = 1;
int attempts = 1;
do
{
failureCode = checkWordVerbose("Enter the word of the day: ", correctWord, attempts);
attempts++;
} while(failureCode == 1);
return failureCode;
}
然后在main中，您需要做的就是检查checkWord(String correctWord)是否返回0.重复相同的事情进行其他检查（或者您甚至可以使用一些相同的功能），执行另一个在第一个内部，例如：
if(checkWord("tired") == 0)
{
if(checkMath("24") == 0)
{
// Success!
}
}
答案 2 :(得分：1)
除非我遗漏了某些东西，否则你正在等待第一次输入，如果它是错误的，你将进入一个do-while循环，然后再也不会检查输入是否正确。
你必须在do-while循环中移动if：
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int attempt = 2;
int answer = 24;
long phoneNumber = 0;
String firstName = "";
String lastName = "";
String wordOfTheDay = "";
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
do {
if (wordOfTheDay.equals("tired")) {
for (attempt = 2; attempt >= 0; --attempt) {
System.out.print(" 3 * 8 = ");
answer = input.nextInt();
input.nextLine();
if (answer == 24) {
System.out
.printf("Please enter your first name, last name, and phone number (no dashes or spaces)\n"
+ "in a drawing for an all-expenses-paid vacation in the Bahamas: ");
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
System.out
.printf("Thank you %s %s. We'll call you at %d if you're a winner.",
firstName, lastName, +phoneNumber);
}
else if (answer != 24) {
if (attempt != 0) {
System.out
.printf("Invalid! Try Again! %d attempt(s) left!\n ",
attempt);
continue;
} else {
System.out
.print("Sorry! You have no more attempts left!");
}
}
}
} else {
System.out.printf("Invalid! Try Again! %d attempt(s) left!\n ",
attempt);
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if (!wordOfTheDay.equals("tired")) --attempt;
}
} while (attempt >= 1);
if (attempt == 0) {
System.out.print("Sorry! You have no more attempts left!");
}
System.exit(0);
}
答案 3 :(得分：1)
通常情况下，您会使用break语句，但由于您不允许设置attempt = -1会产生相同的效果：
if( answer == 24)
{
...
attempt = -1; // An ugly 'break'
}
编辑：
将do { } while();移至if检查之前：
// These two lines of code are no longer required.
//System.out.printf("Enter the word of the day: ");
//wordOfTheDay = input.nextLine();
do
{
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if(!wordOfTheDay.equals("tired"))
{
System.out.printf(
"Invalid! Try Again! %d attempt(s) left!\n ", --attempt);
}
else
{
attempt = 0; // Another ugly 'break'
}
} while (attempt >= 1);
if(wordOfTheDay.equals("tired"))
{
}
// Remove else branch as not required.
答案 4 :(得分：0)
当你得到正确的结果时，你需要离开循环。这是使用break语句完成的：
if( answer == 24)
{
System.out.printf( "Please enter your first name, last name, and phone number (no dashes or spaces)\n" +"in a drawing for an all-expenses-paid vacation in the Bahamas: " );
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
System.out.printf( "Thank you %s %s. We'll call you at %d if you're a winner.", firstName, lastName, + phoneNumber);
break;
// that's the break statement
}
答案 5 :(得分：0)
嗯，显然你必须打破外环。
当你在if块中有正确答案（即'answer == 24'）时，将一些布尔变量'haveAnswer'设置为'true'（初始化为'false'并检查'系统'之前的外循环.out.print（“3 * 8 =”）;'for'if（haveAnswer）{break;}'
enter code here`public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
int attempt = 2;
int answer = 24;
long phoneNumber = 0;
String firstName = "";
String lastName = "";
String wordOfTheDay = "";
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if(wordOfTheDay.equals("tired"))
{
boolean haveAnswer = false;
for( attempt = 2; attempt >= 0; --attempt)
{
if (haveAnswer)
break;
System.out.print(" 3 * 8 = ");
answer = input.nextInt();
input.nextLine();
if( answer == 24)
{
System.out.printf( "Please enter your first name, last name, and phone number (no dashes or spaces)\n" +"in a drawing for an all-expenses-paid vacation in the Bahamas: " );
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
System.out.printf( "Thank you %s %s. We'll call you at %d if you're a winner.", firstName, lastName, + phoneNumber);
haveAnswer = true;
break;
}
else if( answer != 24)
{
if(attempt!=0)
{
System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
continue;
}
else
{
System.out.print( "Sorry! You have no more attempts left!" );
}
}
}
}
else
{
do
{
System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
--attempt;
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
} while (attempt >= 1);
if( attempt == 0)
{
System.out.print( "Sorry! You have no more attempts left!" );
}
}
System.exit(0);
}
}
答案 6 :(得分：0)
此代码不完整，但它具有您需要的ide。试一试。
boolean firstTry = true; boolean keepLooping = true;
do
{
if(!firstTry){
System.out.printf( "Invalid! Try Again! %d attempt(s) left!\n ", attempt);
}
System.out.printf("Enter the word of the day: ");
wordOfTheDay = input.nextLine();
if(wordOfTheDay.equals("hey!")){
keepLooping = false;
}
--attempt;
} while (attempt >= 1 && keepLooping);
答案 7 :(得分：0)
你最好用一个休息时间跳出循环。否则循环将继续，打印“3 * 8 =”并等待你的输入。 如果你不打算使用休息，那么使尝试= -1也是有意义的。
if( answer == 24)
{
System.out.printf( "Please enter your first name, last name, and phone number (no dashes or spaces)\n" +"in a drawing for an all-expenses-paid vacation in the Bahamas: " );
firstName = input.next();
lastName = input.next();
phoneNumber = input.nextLong();
attempt = -1;
System.out.printf( "Thank you %s %s. We'll call you at %d if you're a winner.", firstName, lastName, + phoneNumber);
}