如果使用Redis进行任何性能测量 它可以处理多少个同时订阅/频道?
答案 0 :(得分:1)
我还没有看到这方面的基准,但推动订阅频道的复杂性在于O(N)系列。 来自文档:
PUBLISH:
O(N+M) where N is the number of clients subscribed to the
receiving channel and M is the total number of subscribed
patterns (by any client).
PSUBSCRIBE(订阅模式):
O(N) where N is the number of patterns the client is already subscribed to.
SUBSCRIBE:
O(N) where N is the number of channels to subscribe to.