我正在使用数据库。当我第一次更新我的字段数据库正在更新。但是当我尝试更新下次没有更新但它显示数据库正在更新。我知道问题出在哪里.Thanks!
-(void) updateData {
sqlite3_stmt *statement;
details = [updateArray objectAtIndex:0];
NSString *destinationPath = [self getDestinationPath];
const char *dbpath = [destinationPath UTF8String];
if (sqlite3_open(dbpath, &database) == SQLITE_OK)
{
NSString *updateSQL = [NSString stringWithFormat: @"UPDATE BirthdayRemainderList SET FirstName=\"%@\", LastName=\"%@\",Dob=\"%@\",Address=\"%@\",City=\"%@\",State=\"%@\",Email=\"%@\",Phone=\"%@\" WHERE ids=%@",details.firstNameString,details.lastNameString,details.dobString,details.addressString,details.cityString,details.stateString,details.emailString,details.PhoneString,details.ids];
const char *insert_stmt = [updateSQL UTF8String];
sqlite3_prepare_v2(database, insert_stmt, -1, &statement, NULL);
if (sqlite3_step(statement) == SQLITE_DONE)
{
NSLog(@"Row updated");
}
else {
NSLog(@"Failed to update row");
}
sqlite3_finalize(statement);
sqlite3_close(database);
}
}
我的更新代码在这里
-(IBAction) update
{
AppDelegate *delegate = (AppDelegate *)[[UIApplication sharedApplication] delegate];
savedData = [[DetailsClass alloc] init];
savedData.firstNameString = firstName.text;
savedData.lastNameString = lastName.text;
NSLog(@"last name is %@",savedData.lastNameString);
savedData.dobString = dob.text;
savedData.addressString = address.text;
savedData.cityString = city.text ;
NSLog(@"Changed city value is %@",savedData.cityString);
savedData.stateString = state.text;
savedData.emailString = email.text;
NSLog(@"Changes state value is %@",savedData.emailString);
savedData.PhoneString = phone.text;
NSLog(@"Phone no is %@",savedData.PhoneString);
savedData.ids = idString;
NSLog(@"details in id %@",savedData.ids);
[delegate.updateArray addObject:savedData];
[delegate updateData];
}
这会犯任何错误吗? 如果我们使用两个不同的数组进行保存和更新,它会有什么不同吗?
让我知道问题出在哪里。谢谢!
答案 0 :(得分:1)
添加sqlite错误消息以更深入地了解真正的问题。
sqlite3_prepare_v2(database, insert_stmt, -1, &statement, NULL);
if (sqlite3_step(statement) == SQLITE_DONE)
{
NSLog(@"Row updated");
}
else {
NSLog(@"Failed to update row %s", sqlite3_errmsg(database));
}
如果sql db很忙,它会发生。如果你在firefox的插件等其他地方打开过,请确保关闭数据库。