Question

我有listview，它通过KEY_TITLE（字段）从sqlite和组绑定，所以我需要获取被点击的项目的名称

   @Override
    protected void onListItemClick(ListView l, View v, int position, long id)
    {
        super.onListItemClick(l, v, position, id);
        Intent i=new Intent(this,detail.class);

        i.putExtra(DatabaseIN.KEY_TITLE,SOMETHING THAT I NEED!);

        //startActivity(i);
        startActivityForResult(i,ACTIVITY_EDIT);
    }

//也许像这个字符串selectedIteme = l.getSelectedItem（）。getSOMETNIG？

Answer 1

查看本教程可能会对您有所帮助 http://www.vogella.de/articles/AndroidListView/article.html

您可以像这样选择所选的项目值

 @Override
        protected void onListItemClick(ListView l, View v, int position, long id) {
            Cursor c = (Cursor) arg0.getAdapter().getItem(arg2);

Intent i=new Intent(getApplicationContext(),Xyz.class);
i.putExtra("abc", c.getString(1));
startActivity(i);
    }

Answer 2

在onClick方法中试试这个..

Map<String, String> selection = (Map<String, String>) listView.getItemAtPosition(position);
 String count = selection.get("count");
 String title = selection.get("title");

在Listview列表项目上单击如何获取所选项目的标题（名称）？安卓

2 个答案: