Soccer
Australia
Melbourne
Sydney
New Zealand
Christchurch
Tennis
United Kingdom
Kensington
London
Manchester
我尝试了多维数组,但由于长度不同,它变得很笨拙。我也尝试过键/值对但是我再次遇到了困难,因为在某种程度上只有值而没有键。我试图直观地表示层次结构。澄清悉尼是澳大利亚的孩子。澳大利亚是足球的孩子。足球是网球的兄弟等等。
编辑:我正在寻找一种不需要任何实际数据知识的解决方案。换句话说,我可以用“棒球”替换“足球”,并且只打印出数据结构的简单算法不应该破坏。
答案 0 :(得分:4)
在JSON中:
{
"Soccer": {
"Australia": [
"Melbourne",
"Sydney"
],
"NewZealand": [
"Christchurch"
]
},
"Tennis": {
"UnitedKingdom": [
"Kensington",
"London",
"Manchester"
]
}
}
以下是数据循环:
for ( sport in data ) {
// print sport here
countries = data[sport];
for ( country in countries ) {
// print country here
cities = countries[country];
for (var i = 0; i < cities.length; i++) {
// print city here
};
};
};
可以在jsFiddle上看到:http://jsfiddle.net/2p6g3/18/
答案 1 :(得分:0)
{
"sport": [
{
"name": "Soccer",
"place": [
{
"country": "Australia",
"city": [
{
"name": "Melbourne"
},
{
"nam": "Sdney"
}
]
},
{
"country": "NewZealand",
"city": [
{
"name": "Christchurch"
}
]
}
]
},
{
"name": "Tennis",
"place": [
{
"country": "UnitedKingdom",
"city": [
{
"name": "Manchester"
}
]
}
]
}
]
}
遍历对象数组以获取必填字段:
sport[].name // name of the sports
sport[].place[].country // country name
sport[].place[].city[].name // city name