Question

我有多行数据都共享相同的公司ID。

有没有办法使用SQL Server Management Studio 2005“汇总”所有金额，以便为每个公司ID提供一行数据？

例如我目前有以下数据......

Company_Name   Company_ID   Amount
Company 6         10024   120
Company 6         10024   569
Company 6         10024    53
Company 6         10024   100
Company 6         10024   564
Company 7         10638  9500
Company 7         10638   105
Company 7         10638   624

我想尝试得到的是.......

Company_ Name   Company_ID     Amount 
Company 6        10024         1406
Company 7        10638        10229

有没有办法做到这一点？

任何以正确方式指出我的建议都会很棒。

谢谢，

Answer 1

SELECT Company_Name, Company_ID, SUM(Amount) 
FROM TableName GROUP BY Company_Name, Company_ID

Answer 2

SELECT Company_Name, Company_ID, sum(Amount)
FROM your table
GROUP BY Company_Name, Company_ID

Answer 3

试试这个;

SELECT Company_Name, Company_ID, SUM(Amount) AS Amount
FROM Companies
GROUP BY Company_Name, Company_ID;

演示here。

Answer 4

SELECT Company_Name, Company_ID, sum(Amount)
FROM table
group by Company_Name, Company_ID

Answer 5

您需要使用GROUP BY和SUM功能。

SELECT Company_Name, Company_ID, SUM(Amount) AS TOTAL_AMOUNT
FROM myTable
GROUP BY Company_Name, Company_ID

Answer 6

WITH T ( Company_Name, Company_ID, Amount )
     AS
     (
      SELECT 'Company 6', '10024', 120 UNION ALL
      SELECT 'Company 6', '10024', 569 UNION ALL
      SELECT 'Company 6', '10024', 53 UNION ALL
      SELECT 'Company 6', '10024', 100 UNION ALL
      SELECT 'Company 6', '10024', 564 UNION ALL
      SELECT 'Company 7', '10638', 9500 UNION ALL
      SELECT 'Company 7', '10638', 105 UNION ALL
      SELECT 'Company 7', '10638', 624 
     )
SELECT DISTINCT Company_Name, Company_ID, 
       SUM(Amount) OVER (PARTITION BY Company_ID) AS total_amount
  FROM T;

Answer 7

为我工作：

    select Company_Name   , Company_ID   ,sum(Amount) as 'Amount' from Company group by 
Company_Name,Company_ID   ;

Answer 8

create table #tempTable
(
    Id bigint,
    Title varchar(100),
    Amount money
)
insert into #TempTable(Title,Id,Amount)
Values
('Company 6',         10024,   120),
('Company 6',         10024,   569),
('Company 6',         10024,    53),
('Company 6',         10024,   100),
('Company 6',         10024,   564),
('Company 7',         10638,  9500),
('Company 7',         10638,   105),
('Company 7',         10638,   624)


select Title, Sum(Amount)Amount from #TempTable
group by Title,ID

drop Table #TempTable

如何在sql中对多行进行求和

8 个答案: