Question

目前正在使用cloud / azure和windows phone 7开展项目，我必须致电服务。

对我来说，方便我休息，但我遇到了问题; 我不知道我的上诉何时完成。

public static bool CreateUser(User userToCreate)
{
    if (CheckNetwork())
    {
        var client = new RestClient(Global.Url);
        var request = new RestRequest("/user", Method.POST);

        MemoryStream ms = new MemoryStream();
        DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(User));
        ser.WriteObject(ms, userToCreate);
        string json = JsonHelper.ToJson(userToCreate);

        request.AddHeader("Content-type", "application/json; charset=utf-8");

        request.AddParameter("application/json; charset=utf-8", json, ParameterType.RequestBody);
        request.RequestFormat = DataFormat.Json;

        try
        {
            object resp = null;
            client.ExecuteAsync(request, response =>
                                             {
                                                 if (response.ResponseStatus == ResponseStatus.Completed)
                                                 {
                                                     RestResponse resource = response;
                                                     string content = resource.Content;
                                                     resp = Convert.ToBoolean(JsonHelper.FromJson<string>(content));
                                                 }

                                             });

            return (bool)resp;
        }
        catch (Exception e)
        {
            MessageBox.Show(e.ToString());
            return false;
        }
    }
    MessageBox.Show("You are not connect to the network!");
    return false;
}

在此示例中，该方法在调用服务之前首先返回“resp”。我怎么能确定在resp没有被填充之前我不退出这个方法？

Answer 1

EventWaitHandle Wait = new AutoResetEvent(false);

client.ExecuteAsync(request, response =>
{
    if (response.ResponseStatus == ResponseStatus.Completed)
    {
        RestResponse resource = response;
        string content = resource.Content;
        resp = Convert.ToBoolean(JsonHelper.FromJson<string>(content));
        Wait.Set();
    }
});

Wait.WaitOne();

休息时请确保异步方法已完成

1 个答案: