带有空格的file_get_contents

Question

我有一个问题，即使我将空格替换为％20并将此内容作为终极网址，浏览器将“％20”变为“％2520”

这是我的代码，有什么建议让这个工作？这似乎很容易，但我卡住了：/

<?php
//$_GET['song'] will contain a song name with spaces
$song = str_replace(array("%20", "&", "?" , "/"), array(" ", "", "", ""), $_GET['song']);

// I use this to check how the GET 'song' looks after the str_replace
$list = "http://www.lyrdb.com/lookup.php?q=" . $song . "&for=fullt";
echo "list url is " . $list . "<hr>";

$content = file_get_contents("http://www.lyrdb.com/lookup.php?q=" . str_replace(" ", "%20", $song) . "&for=fullt");

echo $content;
?>

如果你转到http://webservices.lyrdb.com/lookup.php?q=red%20hot%20chili%20peppers&for=fullt结果应该输出一个歌词代码列表。

当我访问我的网站/？song =红辣椒时，它也将空格转换为％20，但如果浏览器似乎将％'转换为％25。

有人能帮助我吗？

Answer 1

$song = $_GET['song']);

$url = "http://www.lyrdb.com/lookup.php?for=fullt&q=";

echo "list url is " . htmlentities($url . $song) . "<hr>";

$content = file_get_contents($url . urlencode($song));

echo $content;

Answer 2

$data = json_encode($_POST);

$url = "http://www.index.com?data=";

echo file_get_contents($url . urlencode($data));