我希望用户通过向消息和“是”或“否”按钮显示对话来确认操作。如何显示,并根据他们选择的按钮执行操作?
谢谢,AlertDialog看起来像我正在寻找的。但是,有一个错误,它说"AlertDialog.Builder(this);"
告诉我,"The constructor AlertDialog.Builder(new View.OnClickListener(){}) is undefined"
-
答案 0 :(得分:4)
如图所示here:
private static final int DIALOG = 1;
显示对话框调用
showDialog(DIALOG);
覆盖onCreateDialog,使用开关检查对话框ID并插入
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("Are you sure about this?")
.setCancelable(false)
.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
// whatever if YES
}
})
.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
// whetever if NO
}
});
AlertDialog alert = builder.create();
答案 1 :(得分:3)
您正在寻找的是AlertDialog
。使用示例here,您可以轻松创建一个“是/否”对话框,该对话框将显示以下内容:
答案 2 :(得分:1)
您创建一个新的AlertDialog.Builder
,传递一些参数,最后调用其create()
方法,并将返回值分配给AlertDialog
对象以保存对它的引用。
AlertDialog.Builder adb = new AlertDialog.Builder(this);
adb.setTitle("Question");
adb.setMessage(Html.fromHtml("Visit Stackoverflow?"));
adb.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// Action for YES
startActivity(
new Intent(
Intent.ACTION_VIEW,
Uri.parse("http://www.stackoverflow.com")));
return;
}
});
adb.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
// Action for NO
return;
}
});
AlertDialog myDialog = adb.create();
答案 3 :(得分:1)
这很简单,如下所示
new AlertDialog.Builder(this)
.setTitle("Info")
.setMessage("hello")
.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
// Some stuff to do when ok got clicked
}
})
.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
// Some stuff to do when ok got clicked
}
})
.show();