我正在尝试使用ResultSetHandler将学生列表传递给servlet但得到以下错误
java.lang.NumberFormatException: For input string: "id"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
Student类中的方法是
public List<Student> list2() throws SQLException {
Connection connection = null;
List<Student> studentList = null;
try {
Context initCtx = new InitialContext();
Context envCtx = (Context) initCtx.lookup("java:comp/env");
DataSource ds = (DataSource)
envCtx.lookup("jdbc/TestDB");
connection = ds.getConnection();
ResultSetHandler h = new ArrayListHandler();
QueryRunner run = new QueryRunner(ds);
String sql = "select student_id, student_name from tbl_student";
studentList = (List<Student>)run.query(sql, h);
}catch(SQLException sqle) {
sqle.printStackTrace();
}
catch(Exception e) {
e.printStackTrace();
}
finally {
DbUtils.closeQuietly(connection);
}
return studentList;
}
我不使用DButils的替代方法工作正常。
public List<Student> list() throws SQLException {
Connection connection = null;
Statement statement = null;
ResultSet resultSet = null;
List<Student> studentList = new ArrayList<Student>();
try {
Context initCtx = new InitialContext();
Context envCtx = (Context) initCtx.lookup("java:comp/env");
DataSource ds = (DataSource)
envCtx.lookup("jdbc/TestDB");
connection = ds.getConnection();
statement = connection.createStatement();
resultSet = statement.executeQuery("select student_id, student_name from tbl_student");
while (resultSet.next()) {
Student student = new Student();
student.setId(resultSet.getInt("student_id"));
student.setName(resultSet.getString("student_name"));
studentList.add(student);
}
}catch(SQLException e) {
e.printStackTrace();
}
catch(Exception e) {
e.printStackTrace();
}
finally {
if (resultSet != null) try { resultSet.close(); } catch (SQLException logOrIgnore) {}
if (statement != null) try { statement.close(); } catch (SQLException logOrIgnore) {}
if (connection != null) try { connection.close(); } catch (SQLException logOrIgnore) {}
}
return studentList;
}
我该如何解决这个问题?
答案 0 :(得分:7)
我建议您使用BeanListHandler从ResultSet中获取所有行,并将它们转换为JavaBeans列表,如下所示:
QueryRunner queryRunner = new QueryRunner(dataSource);
ResultSetHandler<List<Student>> resultSetHandler = new BeanListHandler<Student>(Student.class);
List<Student> studentList = queryRunner.query("SELECT student_id, student_name FROM tbl_student", resultSetHandler);
答案 1 :(得分:0)
如果列名与Bean的属性不匹配,请使用columntoPropertyOverrrides,这将是解决此问题的最佳方法。
public <T> List<T> queryBeanList(String sql, final Class<T> clazz,final Map<String, String> columnToPropertyOverrides) throws SQLException {
ResultSetHandler<List<T>> rsh = new ResultSetHandler<List<T>>(){
@Override
public List<T> handle(ResultSet rs) throws SQLException {
BeanProcessor bp = new BeanProcessor(columnToPropertyOverrides);
return bp.toBeanList(rs, clazz);
}
};
return query(sql, rsh);
}