Question

我有这个链接http://lazhalazha.livejournal.com/data/rss里面有RSS，我需要得到的是guid值数组，这是指向帖子的链接。这就是我到目前为止......

$xml = simplexml_load_file('http://lazhalazha.livejournal.com/data/rss');
foreach ($xml->channel->item as $item){
    print_r($item->guid);
}

输出是这些对象的系列

SimpleXMLElement Object
(
    [@attributes] => Array
        (
            [isPermaLink] => true
        )

    [0] => http://lazhalazha.livejournal.com/713.html
)

通过将此对象转换为字符串来解决此问题，然后传递正确的URL而不是对象。

$xml = simplexml_load_file('http://lazhalazha.livejournal.com/data/rss');
$linkArray = array();
foreach ($xml->channel->item as $item){
    $guid = (string)$item->guid;
    array_push($linkArray, $guid);
}

Answer 1

<?php
$_temp = array();
$xml = simplexml_load_file('http://lazhalazha.livejournal.com/data/rss');

foreach ($xml->channel->item as $item){
    $_temp[] = (string)$item->guid[0];
}

print_r($_temp);
?>

PHP对象 - 如何访问此值

1 个答案: