在EF CodeFirst Fluent API中,我可以这样写:
modelBuilder.Entity<MyEntity>()
.Ignore(e => e.Property1);
modelBuilder.Entity<MyEntity>()
.Ignore(e => e.Property2);
如何忽略所有属性,只需要一小部分,如下:
modelBuilder.Entity<MyEntity>()
.IgnoreAllBut(e => e.ID, e => e.Important);
是否可以编写像IgnoreAllBut
这样的扩展方法?
答案 0 :(得分:3)
这是草稿,但有效:
public static void IgnoreAllBut<TStructuralType>(
this StructuralTypeConfiguration<TStructuralType> configuration,
params Expression<Func<TStructuralType, object>>[] includes)
where TStructuralType : class
{
var includeMembers = ConvertExpressionsToMembers(includes);
var type = typeof(TStructuralType);
var properties = type.GetProperties();
var typeParameter = Expression.Parameter(type);
var configurationType = configuration.GetType();
var ignoreMethod = configurationType.GetMethod("Ignore");
foreach (var property in properties)
{
if (!includeMembers.Any(member => member.Name == property.Name))
{
var propertyExpression = Expression.Property(typeParameter, property);
var lambdaExpression = Expression.Lambda(propertyExpression, typeParameter);
var genericIgnoreMethod = ignoreMethod.MakeGenericMethod(property.PropertyType);
var parameters = new object[] { lambdaExpression };
genericIgnoreMethod.Invoke(configuration, parameters);
}
}
}
private static List<MemberInfo> ConvertExpressionsToMembers<TStructuralType>(
Expression<Func<TStructuralType, object>>[] expressions)
{
var members = new List<MemberInfo>();
foreach (var lambda in expressions)
{
var expression = lambda.Body;
var memberExpression = expression as MemberExpression;
if (memberExpression == null)
{
var unaryExpression = expression as UnaryExpression;
memberExpression = unaryExpression.Operand as MemberExpression;
}
members.Add(memberExpression.Member);
}
return members;
}
感谢DarkGray提供链接question中的代码。