Question

我有用户表单，其中有一个用户名字段。表单中的字段是从数据库中的数据初始化的。

class PersonEditForm(forms.ModelForm):

    username = forms.RegexField(label=_("Username"), max_length=30, regex=r'^[\w.@+-]+$',
    help_text = _("Required. 30 characters or fewer. Letters, digits and @/./+/-/_ only."),
    error_messages = {'invalid': _("This value may contain only letters, numbers and @/./+/-/_ characters.")})


class Meta:
    model = User

view.py

@login_required
def edit(request, template_name):

    if request.user.is_authenticated():
        if request.method == 'POST':
            form = PersonEditForm(request.POST)
            if form.is_valid():
                form.save(instance = request.POST, user = request.user)
                return HttpResponseRedirect(reverse('/success/'))

        else:
            user = User.objects.get(username = request.user)
            form = PersonEditForm(instance = user, initial = {'username': request.user.username})

            return render_to_response(template_name, {"form": form },
                              context_instance = RequestContext(request))

登录用户可以编辑用户名。问题是在编写 clean_username 方法时，我需要request.user来检查：

if username == request.user.username #return true
elif username！= request.user.username

a）User.objects.get（用户名=用户名）#if返回一些东西，然后引发forms.ValidationError（_（＆＃34;用户名已经采取。＆＃34;））

b）否则user.username = username

我怎样才能做到这一点？

Answer 1

您可以在self.instance

中获取

class PersonEditForm(forms.ModelForm):
    def clean_username(self):
        # self.instance is your current user

    ...

视图应如下所示

if request.user.is_authenticated():
    if request.method == 'POST':
        form = PersonEditForm(request.POST, instance=request.user)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect(reverse('/success/'))

    else:
        form = PersonEditForm(instance=request.user, initial={'username': request.user.username})

    return render_to_response(template_name, {"form": form },
                          context_instance = RequestContext(request))

清理django user.username

1 个答案: