Question

我有一个词典

x={'a':[1,'inr','in-gaap'],'b':[2,'','in-gaap'],'c':[3,'inr','']}

我打印的是这样的：

for key,values in x.iteritems():
    print 'value:{0}ref:{1}pre:{2}'.format(x[key][0],x[key][1],x[key][2])

它的打印

value:1 ref:inr pre:in-gaap
value:2 ref:    pre:in-gaap
value:3 ref:inr pre:

但我想要的输出是

value:1 ref:inr pre:in-gaap
value:2 pre:in-gaap
value:3 ref:inr

对于不存在的值，不应打印值。我怎么能这样做？

Answer 1

NAMES = 'value ref pre'.split()
for key, values in x.iteritems():
    valstrs = ['%s:%s' % (name, value)
               for name, value in zip(NAMES, values)
               if value]
    print ' '.join(valstrs)

同时打印如何跳过不在dict中的值

1 个答案: