Question

所以我有代码：

if bulletaloc == bulletcount or bulletbloc == bulletcount and bulletcount % 2 == 0:
        print("Ow!", paname + "'s guts were spilled all over the floor")
 if bulletaloc == bulletcount or bulletbloc == bulletcount and bulletcount % 2 == 1:
        print("Whoops!", pbname, "just got killed...")

我想要它做的是当bulletaloc == bulletcount或当bulletbloc == bulletcount，AND时，这适用于两个条件......当bulletcount％2 == 9时，打印第一条消息。因此，当前两个语句中的任何一个为真时（bulletaloc ...和bulletbloc ...，并且第三个为真，请打印该消息。）无论如何，最终发生的是两条消息都打印出来！我该如何解决这个问题？

Answer 1

您应该了解or和and的优先顺序：

>>> True or False and False
True
>>> (True or False) and False
False
>>> True or (False and False)
True

我会像这样重构它：

if bulletcount in (bulletaloc, bulletbloc):
  if bulletcount % 2:
    print("Whoops! {} just got killed...".format(pbname))
  else:
    print("Ow! {}'s guts were spilled all over the floor".format(paname))

或者和陈述，正确的方法

1 个答案: