Question

我已经编写了这段代码来查找重复内容并且工作正常：

SELECT *
FROM StyleTable 
GROUP BY Color
HAVING count(*) > 1

问题是，它只返回一个重复的行。是否可以返回所有重复的行？我猜这可能与'GROUP BY'有关，但我不知道如何改变它。我不想删除它们，只需返回它们。

Answer 1

你必须再次加入桌面以获得重复的内容。类似的东西：

SELECT * 
FROM StyleTable 
WHERE Color IN (
  SELECT Color  
  FROM StyleTable   
  GROUP BY Color  
  HAVING count(*) > 1 
)

Answer 2

SELECT s.*
    FROM StyleTable s
        INNER JOIN (SELECT Color
                        FROM StyleTable
                        GROUP BY Color
                        HAVING COUNT(*) > 1) q
            ON s.Color = q.Color

Answer 3

WITH cte AS ( SELECT FirstName, LastName,COUNT(*) occurrences FROM Customer GROUP BY FirstName, LastName HAVING COUNT(*) > 1)
SELECT * FROM Customer INNER JOIN cte ON 
        cte.FirstName = Customer.FirstName AND 
        cte.LastName = Customer.LastName
ORDER BY Customer.FirstName, Customer.LastName

返回所有重复的行

3 个答案: