**编辑:我找到了解决方案。**
对于那些敢于阅读以下内容的人,我有一个奇怪的问题:
我正在做家庭作业,需要使用UNIX管道在进程之间发送消息。
我对此代码的意图是在提供的文件描述符上选择()。如果有什么东西可以不受阻塞地阅读,我想要返回它。如果没有,我想返回NULL并继续而不阻塞。
这是我的“getMessage”函数里面的代码,其中fd是文件描述符:
message* getMessage(int fd){
int messageAvailable = 0;
struct timeval timeout;
fd_set fd2;
//If there's a message available, read it; if not, continue on without delay
timeout.tv_sec = 0;
timeout.tv_usec = 0;
FD_ZERO(&fd2);
FD_SET(fd,&fd2);
messageAvailable = select(FD_SETSIZE,&fd2,NULL,NULL,&timeout);
if(messageAvailable){
int bytesRead = 0;
message* m;
m = malloc(sizeof(message));
//Get the header
bytesRead = read(fd,m,sizeof(message));
//If we got the whole message
if(bytesRead == sizeof(message)){
return m;
}else{
//If a message wasn't generated, free the space we allocated for it
free(m);
return NULL;
}
}else{
return NULL;
}
}
此代码位于循环内部,该循环在程序的持续时间内持续,并且在完全相同的点(成功传输一条消息后的下一个getMessage()调用)之后会出现段错误。显然,FD_SET线正在从无效的内存位置读取。
如果不发布我的所有代码,是否有人可以猜测在这个简单的宏中导致段错误的原因是什么?
我在下面发布了相关的调试信息,其中第33行与上面的FD_SET行对应:
==1330== Invalid read of size 1
==1330== at 0x804E819: getMessage (messages.c:33)
==1330== by 0x8049123: main (messageTest.c:110)
==1330== Address 0xde88d627 is not stack'd, malloc'd or (recently) free'd
==1330==
==1330==
==1330== Process terminating with default action of signal 11 (SIGSEGV)
==1330== Access not within mapped region at address 0xDE88D627
==1330== at 0x804E819: getMessage (messages.c:33)
==1330== by 0x8049123: main (messageTest.c:110)
==1330== If you believe this happened as a result of a stack
==1330== overflow in your program's main thread (unlikely but
==1330== possible), you can try to increase the size of the
==1330== main thread stack using the --main-stacksize= flag.
==1330== The main thread stack size used in this run was 8388608.
==1330==
==1330== HEAP SUMMARY:
==1330== in use at exit: 344 bytes in 10 blocks
==1330== total heap usage: 25 allocs, 15 frees, 2,492 bytes allocated
==1330==
==1330== LEAK SUMMARY:
==1330== definitely lost: 12 bytes in 1 blocks
==1330== indirectly lost: 0 bytes in 0 blocks
==1330== possibly lost: 0 bytes in 0 blocks
==1330== still reachable: 332 bytes in 9 blocks
==1330== suppressed: 0 bytes in 0 blocks
==1330== Rerun with --leak-check=full to see details of leaked memory
==1330==
==1330== For counts of detected and suppressed errors, rerun with: -v
==1330== ERROR SUMMARY: 2 errors from 2 contexts (suppressed: 11 from 6)
Segmentation fault
答案 0 :(得分:0)
哎呀......在我做了一些处理之后,我不小心将-1作为FD传递给了函数(这解释了为什么它在每次运行的同一点发生)。
这个问题可能会被关闭;我不认为它在我的单一用例之外有很多用途。