我只是C ++的初学者。我正在编写一个小而简单的程序,它在两个用户指定的整数之间打印一系列整数。
最后,如果用户返回1,程序将重新运行while循环,但是当发生这种情况时,程序将不再打印一系列数字(for循环不起作用)。
这是源代码:
int main(void)
{
int num1, num2;
int doContinue = 1;
while (doContinue == 1)
{
cout << "Please enter two integers, the first being the smallest: ";
do { //does everything in curly braces while the user inputs the numbers wrong...
cin >> num1 >> num2;
if (num1 > num2)
{
cout << "Your first number was bigger than the second.\nTry again!: ";
}
} while (num1 > num2);//... but once it's not wrong, break out of this do loop
//at this point the input has been checked, so we can proceed to print the series
for(int num1; num1 <= num2; num1++)
{
cout << num1 << " \n";
}
cout << "Would you like to compute another series of integers? 1=yes, anything else=no: ";
cin >> doContinue;
}
return 0;
}
答案 0 :(得分:2)
您的代码显示未定义的行为。
for(int num1; num1 <= num2; num1++)
{
cout << num1 << " \n";
}
创建一个名为num1
的新整数,与for循环外的num1
无关。您没有初始化num1
的值,而是继续对其进行比较。
在for循环中删除int num1
(即for(; num1 <= num2; num1++)
之类的内容),然后重试。
答案 1 :(得分:0)
尝试
for(int i = num1; i<= num2; i++)
而不是
for(int num1; num1 <= num2; num1++)
答案 2 :(得分:0)
更改此部分代码
for(int num1; num1 <= num2; num1++)
{
cout << num1 << " \n";
}
到
for( ; num1 <= num2; num1++)
{
cout << num1 << " \n";
}