SQL检测部分重复的行

Question

我有一张表：

ID X
1  YES
1  YES
2  YES
2  YES
2  NO
3  NO
4  NO
4  YES

我需要返回同时包含Yes和No的所有ID，因此最终结果应该是2和4但不是2和3

Answer 1

SELECT ID
    FROM YourTable
    WHERE X IN ('YES', 'NO')
    GROUP BY ID
    HAVING COUNT(DISTINCT X) = 2

Answer 2

试试这个：

select id from t
where x in ('YES', 'NO')
group by id
having count(distinct x) = 2

这是working example

另请注意，如果您的表中只有'YES'和'NO'值（如您的示例中所示），则可以删除where子句，因为它将是不必要的且效率较低。

Answer 3

SELECT DISTINCT ID FROM myTable
WHERE X = 'YES'
     AND ID IN (SELECT DISTINCT ID FROM myTable WHERE X = 'NO')

Answer 4

另一种选择：

SELECT DISTINCT id
  FROM t t1
  JOIN t t2 USING(id)
 WHERE t1.X = 'YES' AND t2.X = 'NO'