我正在上传图片并将其显示在Gridview
。我将图片保存在一个文件夹中,并将名称保存在数据库中。如果我上传了3张图片并且必须删除我选择的图片,我想要。所以我有图片1 2 3.当我选择图片2时,这将被删除..我该怎么办?这是我上传图片的代码:
string filename = Path.GetFileName(fileuploadimages.PostedFile.FileName);
fileuploadimages.SaveAs(Server.MapPath("Images/" + filename));
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["baza_chestionar"].ToString());
con.Open();
SqlCommand cmd = new SqlCommand("Insert into Images(ImageName,ImagePath) values(@ImageName,@ImagePath)", con);
cmd.Parameters.AddWithValue("@ImageName", filename);
cmd.Parameters.AddWithValue("@ImagePath", "Images/" + filename);
cmd.ExecuteNonQuery();
con.Close();
Response.Redirect("~/upload.aspx");
答案 0 :(得分:2)
要删除文件,请使用System.IO.File.Delete
:
File.Delete(Path.Combine(path, filename));
其余的实现细节,您如何通知服务器要删除的相应文件,取决于您。
答案 1 :(得分:1)
您可以使用以下GridView的事件来删除图像..
- RowCommand
- RowDeleting
醇>
protected void grd_RowCommand(object sender, GridViewCommandEventArgs e)
{
grd.Rows[e.RowIndex].FindControl("Control of the file Name");
//Find control that contains file Name
if (System.IO.File.Exists("FilePath"))
{
File.Delete(Path.Combine("path", "FileName"));
}
//Your Delete Code to delete record from database
}
protected void grd_RowDeleting(object sender, GridViewDeleteEventArgs e)
{
grd.Rows[e.RowIndex].FindControl("Control of the file Name");
//Find control that contains file Name
if (System.IO.File.Exists("FilePath"))
{
File.Delete(Path.Combine("path", "FileName"));
}
//Your Delete Code to delete record from database
}
<asp:GridView ID="grd" runat="server" onrowcommand="grd_RowCommand"
onrowdeleting="grd_RowDeleting">
<Columns>
<asp:TemplateField>
<ItemTemplate>
<asp:LinkButton ID="delete" runat="server" Text="Select" CommandName="delete"></asp:LinkButton>
<asp:LinkButton ID="deleteRow" runat="server" Text="Select" CommandName="deleteRow"></asp:LinkButton>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
请注意 - 您可以使用RowCommand/RowDeleting
个活动......我将使用RowDeleting