Question

我正在使用以下SQL Query：

SELECT `comment`.`id` AS `comment_id` , count( `comment_likes`.`comment_id` ) AS `number_of_likes`
FROM `comment`
LEFT JOIN `comment_likes` ON `comment`.`id` = `comment_likes`.`comment_id`
WHERE `comment`.`id`
IN ( 10, 5, 7, 8, 3, 2, 9 )
GROUP BY `comment`.`id`

此处查询的结果如下：

comment_id  number_of_likes
2           0
3           1
5           0
7           0
8           0
9           0
10          0

我不想要......？我想要条件相同的顺序，即 WHERE comment。id IN（10,5,7,8,3,2,9）。

所以我希望结果如下：

comment_id  number_of_likes
10          0
5           0
7           0
8           0
3           1
2           0
9           0

任何人都可以帮助我......？

先谢谢.....

Answer 1

添加显式ORDER BY。一个有用的功能是FIELD()：

ORDER BY FIELD(comment.id, 10, 5, 7, 8, 3, 2, 9)

Answer 2

您需要使用MySQL的FIELD()才能获得所需的结果

SELECT `comment`.`id` AS `comment_id` , 
        count( `comment_likes`.`comment_id` ) AS `number_of_likes`
FROM `comment` LEFT JOIN `comment_likes` ON 
       `comment`.`id` = `comment_likes`.`comment_id`
WHERE `comment`.`id`
IN ( 10, 5, 7, 8, 3, 2, 9 )
GROUP BY `comment`.`id`
ORDER BY FIELD(comment.id, 10, 5, 7, 8, 3, 2, 9)

Group By正在排序我不想要的结果集......？

2 个答案: