我有几个关于eigen的新手问题。
下面是一个很小的功能来说明它们。
我有一个矢量,其大小将从一次迭代增长到下一次,从h = 1到h = h_m,其中h_m int h=10,j=0; while(h<h_m){ //b.0
Indexn1.setLinSpaced(n,0,n-1); //b.1
random_shuffle(Indexn1.data(),Indexn1.data()+n); //b.2
RIndex.resize(h);
RIndex = Indexn1.segment(0,h); //b.3
....
....
j++; //b.4
h=ceil(j/(2.0*J)*(n-p-1)+p+1); //b.5
xSub.resize(h,NoChange);
xS_mean = xSub.colwise().mean() //b.6
} //we always have that h<h_m<n//
//declare the matrix to its final size: //a.3
MatrixXf xSub(h_m,p); //a.1
VectorXi Indexn1(n); //a.2
//declare the vector to its final size: //a.3
VectorXi RIndex(h_m); //a.4
行b_4在运行时导致此错误(经过多次迭代后) b.0-> b.4以上):
eigen / Eigen / src / Core / Block.h:278:Eigen :: Block&lt; XprType,BlockRows,BlockCols,InnerPanel,true&gt; :: Block(XprType&amp;,Eigen :: Block&lt; XprType,BlockRows,BlockCols, InnerPanel,true&gt; :: Index)[with XprType = Eigen :: Matrix&lt; float,-0x00000000000000001,-0x00000000000000001&gt;,int BlockRows = 1,int BlockCols = -0x00000000000000001,bool InnerPanel = false,Eigen :: Block&lt; XprType,BlockRows ,BlockCols,InnerPanel,true&gt; :: Index = long int]:断言`(i&gt; = 0)&amp;&amp; (((BlockRows == 1)&amp;&amp;(BlockCols == XprType :: ColsAtCompileTime)&amp;&amp; i&lt; xpr.rows())||((BlockRows == XprType :: RowsAtCompileTime)&amp;&amp;( BlockCols == 1)&amp;&amp; i&lt; xpr.cols()))'失败 中止
你能帮助理解它的意义所以我可以解决问题吗?
//index of the h smallest elements of the vector dP:
RIndex.resize(h);
RIndex = SSubInd(dP,h);
//constructs the corresponding sub-matrix of elements of x with index given above:
//this is the offending line.
xSub.resize(h,NoChange);
xSub = RSubMatrix(x,RIndex);
仰望RSubMatrix:
MatrixXf RSubMatrix(MatrixXf& x, VectorXi& Index){
MatrixXf xSub(Index.size(),x.cols());
for(int i=0;i<Index.size();i++){
xSub.row(i)=x.row(Index(i));
}
return xSub;
}
:(
答案 0 :(得分:2)
错误消息意味着构造了一个Eigen :: Block(代表一个子矩阵),其索引超出了界限。块在许多地方构建,包括成员函数.row()
。假设错误源自表达式xSub.row(i) = x.row(Index(i))
,则表示i
大于或等于xSub
或x
中的行数。